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2 years ago

Please help

2 answers:

7 0

<h2>Answer:</h2><h2>67.5 square feet</h2><h2></h2><h2>Step-by-step explanation:</h2><h2>Multiply 15 and 9</h2><h2>= 135</h2><h2 /><h2>Divide by 2</h2><h2 /><h2>135 ÷ 2</h2><h2 /><h2>= 67.5</h2>

<h2><u>Final answer: 67.5 square feet</u></h2>

netineya [11]2 years ago

6 0

Answer:

Option c - 67.5

Step-by-step explanation:

Base= 15

Height = 9

Area= 1/2 x b h = 1/2 x 9 x 15 = 67.5 feet

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Find (g • f) ^(3) PLEASE HELLPP

spayn [35]

The first thing we are going to do to find (g°f)(3), is find (g°f)(x). To do that, we are going to evaluate g(x) at f(x):
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Now, we can evaluate (g°f) at 3:
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3 years ago

. On Tuesday, Bellagio's Pizza sold 60 plain pizzas at $5 each; 20 meatball pizzas at $8 each; 25 Sicilian pizzas at $9 each; an

Alexeev081 [22]

The answer is D because

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4 0

3 years ago

What is the value can u show work

Basile [38]

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3 years ago

Given g(x)=-2x+3, solve for x when g(x)=-3

erma4kov [3.2K]

Answer:

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Step-by-step explanation:

Replace all of the (x) with -3

So the new equation

g(-3)= -2(-3)+3

Now simplify

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Hope this helps!

5 0

3 years ago

In analyzing the city and highway fuel efficiencies of many cars and trucks, the mean difference in fuel efficiencies for the 60

Olegator [25]

Answer:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

Step-by-step explanation:

Data provided

$\bar X=7.38$ represent the sample mean for the fuel efficiencies

$\mu$ population mean

s=2.51 represent the sample standard deviation

n=601 represent the sample size

Confidence interval

The formula for the confidence interval of the true mean is given by:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom for this case is given by:

$df=n-1=601-1=600$

The Confidence level for this case is 0.95 or 95%, and the significance level $\alpha=0.05$ and $\alpha/2 =0.025$ and the critical value is given by $t_{\alpha/2}=1.96$

Replcing into the formula for the confidence interval is given by:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

8 0

3 years ago