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9966 [12]
2 years ago
12

Here is a sketch of y=x^2 +bx+c

Mathematics
1 answer:
Norma-Jean [14]2 years ago
7 0

Answer:

Step-by-step explanation:

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The equation of function h is h... PLEASE HELP MATH
Flura [38]

Answer:

Part A: the value of h(4) - m(16) is -4

Part B: The y-intercepts are 4 units apart

Part C: m(x) can not exceed h(x) for any value of x

Step-by-step explanation:

Let us use the table to find the function m(x)

There is a constant difference between each two consecutive values of x and also in y, then the table represents a linear function

The form of the linear function is m(x) = a x + b, where

  • a is the slope of the function
  • b is the y-intercept

The slope = Δm(x)/Δx

∵ At x = 8, m(x) = 2

∵ At x = 10, m(x) = 3

∴ The slope = \frac{3-2}{10-8}=\frac{1}{2}

∴ a = \frac{1}{2}

- Substitute it in the form of the function

∴ m(x) = \frac{1}{2} x + b

- To find b substitute x and m(x) in the function by (8 , 2)

∵ 2 = \frac{1}{2} (8) + b

∴ 2 = 4 + b

- Subtract 4 from both sides

∴ -2 = b

∴ m(x) = \frac{1}{2} x - 2

Now let us answer the questions

Part A:

∵ h(x) = \frac{1}{2} (x - 2)²

∴ h(4) = \frac{1}{2} (4 - 2)²

∴ h(4) = \frac{1}{2} (2)²

∴ h(4) =  \frac{1}{2}(4)

∴ h(4) = 2

∵ m(x) = \frac{1}{2} x - 2

∴ m(16) =  \frac{1}{2} (16) - 2

∴ m(16) = 8 - 2

∴ m(16) = 6

- Find now h(4) - m(16)

∵ h(4) - m(16) = 2 - 6

∴ h(4) - m(16) = -4

Part B:

The y-intercept is the value of h(x) at x = 0

∵ h(x) = \frac{1}{2} (x - 2)²

∵ x = 0

∴ h(0) = \frac{1}{2} (0 - 2)²

∴ h(0) =  \frac{1}{2} (-2)² =  

∴ h(0) = 2

∴ The y-intercept of h(x) is 2

∵ m(x) = \frac{1}{2} x - 2

∵ x = 0

∴ m(0) = \frac{1}{2} (0) - 2 = 0 - 2

∴ m(0) = -2

∴ The y-intercept of m(x) is -2

- Find the distance between y = 2 and y = -2

∴ The difference between the y-intercepts of the graphs = 2 - (-2)

∴ The difference between the y-intercepts of the graphs = 4

∴ The y-intercepts are 4 units apart

Part C:

The minimum/maximum point of a quadratic function f(x) = a(x - h) + k is point (h , k)

Compare this form with the form of h(x)

∵ h = 2 and k = 0

∴ The minimum point of the graph of h(x) is (2 , 0)

∵ k is the minimum value of f(x)

∴ 0 is the minimum value of h(x)

∴ The domain of h(x) is all real numbers

∴ The range of h(x) is h(x) ≥ 2

∵ m(8) = 2

∵ m(14) = 5

∵ h(8) = \frac{1}{2} (8 - 2)² = 18

∵ h(14) = \frac{1}{2} (14 - 2)² = 72

∴ h(x) is always > m(x)

∴ m(x) can not exceed h(x) for any value of x

<em>Look to the attached graph for more understand</em>

The blue graph represents h(x)

The green graph represents m(x)

The blue graph is above the green graph for all values of x, then there is no value of x make m(x) exceeds h(x)

7 0
3 years ago
HELP PLZZZ!!!! What is the approximate area of a circular pond?
Georgia [21]

Answer:

<h2>B. 49,062.5 ft²</h2>

Step-by-step explanation:

The formula of an area of a circle:

A=\pi r^2

r - radius

We have the diameter d = 250 ft. We know: d = 2r.

Therefore r = 250 : 2 = 125 ft.

Substitute:

A=\pi(125)^2=15625\pi

\pi\approx3.14\to A=(15625)(3.14)=49062.5\ ft^2

7 0
3 years ago
If f(x)= x2 + 2x - 6 and g(x)= 3x2 - 5x - 7, find f(x)-g(x).
dezoksy [38]

Answer:

- 2x² + 7x + 1

Step-by-step explanation:

f(x) - g(x)

= x² + 2x - 6 - (3x² - 5x - 7) ← distribute parenthesis by - 1

= x² + 2x - 6 - 3x² + 5x + 7 ← collect like terms

= - 2x² + 7x + 1

8 0
3 years ago
What is the sample space for choosing an odd number from 1 to 11 at random
Black_prince [1.1K]

Answer:

{1, 3, 5, 7, 9, 11}

4 0
3 years ago
Can someone help me with my hw
zmey [24]

I loved doing these! anyway, the answer in order would be..

2x +2

6x +6

20x +4

20x +30

4x +8

12x +6

9x

5x +15

8x +12

24x +12

and 42x +18

Your welcome ;)



3 0
2 years ago
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