3 years ago

What is the equation of a line that passes through the points (3, 6) and (8, 4) in slope intercept form?

Mathematics

1 answer:

MrMuchimi3 years ago

6 0

Answer:

$y=-\frac{2}{5}x +8.4$

Step-by-step explanation:

Gradient

$m =\frac{y-y1}{x-x1}$

$m = \frac{6-4}{3-8}$

$m=-\frac{2}{5}$

Equation of a line

$(y-y1)=m(x-x1)\\$

- Sub one set of points into equation

$(y-6)= -\frac{2}{5} (x-6)$

$y=-\frac{2}{5}x +8.4$

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Given:

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