Question

What is the equation of a line that passes through the points (3, 6) and (8, 4) in slope intercept form?

Answer 1

Answer:

$y=-\frac{2}{5}x +8.4$

Step-by-step explanation:

Gradient

$m =\frac{y-y1}{x-x1}$

$m = \frac{6-4}{3-8}$

$m=-\frac{2}{5}$

Equation of a line

$(y-y1)=m(x-x1)$

- Sub one set of points into equation

$(y-6)= -\frac{2}{5} (x-6)$

$y=-\frac{2}{5}x +8.4$