All categories

3 years ago

What is the equation of a line that passes through the points (3, 6) and (8, 4) in slope intercept form?

Mathematics

1 answer:

MrMuchimi3 years ago

6 0

Answer:

$y=-\frac{2}{5}x +8.4$

Step-by-step explanation:

Gradient

$m =\frac{y-y1}{x-x1}$

$m = \frac{6-4}{3-8}$

$m=-\frac{2}{5}$

Equation of a line

$(y-y1)=m(x-x1)\\$

- Sub one set of points into equation

$(y-6)= -\frac{2}{5} (x-6)$

$y=-\frac{2}{5}x +8.4$

You might be interested in

My sister can walk from school to home in 35 minutes. I can walk from school to home in 20 minutes. But today I stayed for some

Verizon [17]

Answer:

you both will reach the home at the same time.

I) You can catch your sister.

ii) Reason: you both will reach home at the same time.

Step-by-step explanation:

Let "d" be distance from school to home.

Let's find the speed of you and your sister.

Speed = $\frac{Distance}{Time}$

Your speed = $\frac{d}{20}$

Your sister's speed = $\frac{d}{35}$

Today, You stayed for some extra help by the time your sister covered $\frac{3}{7}$ of the way home.

Remaining distance to reach the home = $1 - \frac{3}{7}d = \frac{7-3}{7}d = \frac{4}{7}d$

Now let's find the time to be taken your sister to reach the home.

Time = $\frac{distance}{speed}$

= $\frac{\frac{4}{7}d }{\frac{1}{35} d} = \frac{4}{7} *\frac{35}{1} = 20$

So, your sister will take 20 minutes to get home by the time your start.

We know that it takes you 20 minutes to reach your home.

Therefore, you both will reach the home at the same time.

I) You can catch your sister.

ii) Reason: you both will reach home at the same time.

7 0

3 years ago

. 6.8 • 102<br> Help me c:

AnnZ [28]

Answer:

693.6

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Calculate pt3 such that a line from pt1 to pt3 is perpendicular to the line from pt1 to pt2, and the distance between pt1 and pt

Leni [432]

Let the point_1 = p₁ = (1,4)
and      point_2 = p₂ = (-2,1)
and      Point_3 = p₃ = (x,y)

The line from point_1 to point_2 is L₁ and has slope = m₁
The line from point_1 to point_3 is L₂ and has slope = m₂
m₁ = Δy/Δx = (1-4)/(-2-1) = 1
m₂ = Δy/Δx = (y-4)/(x-1)
L₁⊥L₂ ⇒⇒⇒⇒ m₁ * m₂ = -1
∴ (y-4)/(x-1) = -1 ⇒⇒⇒ (y-4)= -(x-1)
(y-4) = (1-x) ⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒ equation (1)

The distance from point_1 to point_2 is d₁
The distance from point_1 to point_3 is d₂
d = $\sqrt{Δx^2+Δy^2}$
d₁ = $\sqrt{(-2-1)^2+(1-4)^2}$
d₂ = $\sqrt{(x-1)^2+(y-4)^2}$
d₁ = d₂
∴ $\sqrt{(-2-1)^2+(1-4)^2} = \sqrt{(x-1)^2+(y-4)^2}$ ⇒⇒ eliminating the root
∴(-2-1)²+(1-4)² = (x-1)²+(y-4)²
(x-1)²+(y-4)² = 18
from equatoin (1) y-4 = 1-x
∴(x-1)²+(1-x)² = 18            ⇒⇒⇒⇒⇒ note: (1-x)² = (x-1)²
2 (x-1)² = 18
(x-1)² = 9
x-1 = $\pm \sqrt{9} = \pm 3$
∴ x = 4 or x = -2
∴ y = 1 or y = 7

Point_3 = (4,1) or (-2,7)

8 0

4 years ago

Evaluate 2/5 log 32 + (log 9 )/log 3) Please Show Working?

sattari [20]

Simplify the expression

exact form:

log(4)+log(9)/log(3)

Decimal Form:

2.60205999 . . .

Hope this helps! :)

~Zane

6 0

3 years ago

Explain how you got the answer please

Alisiya [41]

The answer is C.
You want:

10 < a < 14 (greater or equal)
The difference between 10 and 12 is 2.
The difference between 12 and 14 is 2.
Therefore the absolute value allows you to express that the difference between a and 12 cannot be greater than 2 (either going up to a max of 14 or going down to a minimum of 10).

5 0

3 years ago