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3 years ago

14

A handyman charges a flat rate of $150, plus $25 per hour for house painting. A painter charges $55 per hour for house painting.

Which equation could be used to determine, h, the number of hours each would have to work for their fees to be the same? 150 – 55h = 25h 150 – 55h = 25h 150 + 25h = 55h 150 + 25h = 55h 150 – 25h = 55h 150 – 25h = 55h 55h + 150 = 25h

2 answers:

FromTheMoon [43]3 years ago

8 0

Answer:

150+25=55

Step-by-step explanation:

i cnt promise the right answer but i tried and

got really confused really quick

hope i helped

Bond [772]3 years ago

4 0

It’s 55 hoped this helped

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∠A and \angle B∠B are vertical angles. If m\angle A=(3x-30)^{\circ}∠A=(3x−30) ∘ and m\angle B=(2x-9)^{\circ}∠B=(2x−9) ∘ , then f

jasenka [17]

Answer:

x = 21

Step-by-step explanation:

Vertical angles are congruent, this

3x - 30 = 2x - 9 ( subtract 2x from both sides )

x - 30 = - 9 ( add 30 to both sides )

x = 21

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An equation whose variables are polar coordinates is called a ____________

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An equation whose variables are polar coordinates is called a polar equation. These equation are characterized by an r as a function an angle. Polar equations can be written in rectangular coordinates by certain relationships. An example of a polar equation would be r = 2sin∅.

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Match each series with the equivalent series written in sigma notation

PIT_PIT [208]

Answer:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

$3 + 12 + 48 + 192 + 768$

The expression can be written as:

$3 \to 3*4^{0$ --- 0

$12 \to 3 * 4^{1$ ---- 1

$48 \to 3 * 4^{2$ --- 2

$192 \to 3 * 4^{3$ ---- 3

$768 \to 3 * 4^{4$ ---- 4

For the nth term, the expression is:

$Term = 3 * 4^{n$ ---- n

So, the summation is:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

Solving (b):

$4 + 32 + 256 + 2048 + 16384$

The expression can be written as:

$4 \to 4 * 8^0$ --- 0

$32 \to 4 * 8^1$ ---- 1

$256 \to 4 * 8^2$ --- 2

$2048 \to 4 * 8^3$ ---- 3

$16384 \to 4 * 8^4$ ---- 4

For the nth term, the expression is:

$Term \to 4 * 8^n$ ---- n

So, the summation is:

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

Solving (c):

$2 + 6 + 18 + 54 + 162$

The expression can be written as:

$2 \to 2 * 3^0$ --- 0

$6 \to 2 * 3^1$ ---- 1

$18 \to 2 * 3^2$ --- 2

$54 \to 2 * 3^3$ ---- 3

$162 \to 2 * 3^4$ ---- 4

For the nth term, the expression is:

$Term \to 2 * 3^n$ ---- n

So, the summation is:

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

Solving (d):

$3 + 15 + 75 + 375 + 1875$

The expression can be written as:

$3 \to 3 * 5^0$ --- 0

$15 \to 3 * 5^1$ ---- 1

$75 \to 3 * 5^2$ --- 2

$375 \to 3 * 5^3$ ---- 3

$1875 \to 3 * 5^4$ ---- 4

For the nth term, the expression is:

$Term \to 3 * 5^n$ ---- n

So, the summation is:

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

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Ierofanga [76]

Answer:

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Step-by-step explanation:

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