Answer:
a) Here we have:
"In Family A, the youngest child is 7 years younger than the oldest, who is 18"
Let's define:
Y = age of the youngest child.
O = age of the oldest child.
Then we know that:
Y = O - 7
O = 18
Then we can replace the second equation into the first one:
Y = 18 - 7 = 11.
b) Here we have:
"In Family B, the middle child is 5 years older than the youngest child."
Let's define:
Y = age of the youngest child.
M = age of the middle child.
Here we have only one equation:
M = Y + 5.
You can round 976 to 1000 and 522 to 500. So it would be
1000 - 500 = 500. The answer you would get after subtracting 976-522 would be more than 400 if you round it.
21 I think I'm not sure tho
SOLUTION
From the given data the mean is 62 and standard deviation is 4
It is required to find the probability that a data value is between 57 and 62
That is:
The z scores is calculated using:
Using the x values it follows:
Also,
Thus the required probability is:
![P(-1.25The proability is:[tex]P(-1.25This can be expressed as percentage as:[tex]P(-1.25\lt z\lt0.75)=66.8\%](https://tex.z-dn.net/?f=P%28-1.25The%20proability%20is%3A%5Btex%5DP%28-1.25This%20can%20be%20expressed%20as%20percentage%20as%3A%5Btex%5DP%28-1.25%5Clt%20z%5Clt0.75%29%3D66.8%5C%25)
Therefore the correct option is C
Answer:
a
Step-by-step explanation:
sec (thita) = squrt (5)
squaring on both sides:
sec^2 (thita) = 5 - equation 1
1 + tan^2 (thita) = 5
tan^2 (thita) = 4
tan (thita) = 2.
= tan (thita) - squrt(5)sin(thita)
= 2 - squrt(5) x 2/ squrt(5)
= 0
from eqn - 1
sec(thita) = squrt(5)
cos(thita) = 1/ squrt(5)
sin(thita) = squrt ( 1- 1/(squrt (5))^2)
sin(thita) = 2/ squrt(5) .
