Answer:
Step-by-step explanation:
Equation of a line is given as 
Where,
m = slope of the line = 
b = y-intercept, which is the value at the point where the line intercepts the y-axis. At this point, x = 0.
Let's find m and b to derive the equation for the line.
Use the coordinate pair of any two points on the line. Let's use the following,
=> on the line, when x = 0, y = -2
=> on the line, when x = 4, y = 1
Plug in the values and solve for m
b = -2 (the line intercepts the y-axis at this point)
Our equation would be =>
Answer:
100 pascals would be your answer
have a great day ! ⭐️
Answer:
In quadrilateral ABCD we have
AC = AD
and AB being the bisector of ∠A.
Now, in ΔABC and ΔABD,
AC = AD
[Given]
AB = AB
[Common]
∠CAB = ∠DAB [∴ AB bisects ∠CAD]
∴ Using SAS criteria, we have
ΔABC ≌ ΔABD.
∴ Corresponding parts of congruent triangles (c.p.c.t) are equal.
∴ BC = BD.
<h3>
Answer: G) -2</h3>
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Explanation:
I'm assuming you meant to say (a+y)^2 + 2y
Replace each copy of 'a' with 5. Replace each copy of 'y' with -3. Use PEMDAS to simplify.
(a+y)^2 + 2y
(5 + (-3))^2 + 2(-3)
(5-3)^2 + 2(-3)
(2)^2 + 2(-3)
4 + 2(-3)
4 - 6
-2
So (a+y)^2 + 2y = -2 when a = 5 and y = -3.
