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3 years ago

3(x-2) >-3 Anyone could help

Mathematics

2 answers:

rusak2 [61]3 years ago

7 0

Firstly, foil 3(x - 2): $3x-6>-3$

Next, add 6 on both sides of the inequality: $3x>3$

Next, divide both sides by 3, and your inequality is $x>1$ 

yan [13]3 years ago

3 0

3(x - 2) > -3

...multiply 3

3x - 6 > -3

...add 6

3x > 3

...divide 3

x > 1

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It cost 5 dollars for a child ticket and 8 dollars for a adult ticket. Total tickets sold were 110 bringing in 820 dollars? How

omeli [17]

Number of child tickets bought is 20

<h3>Solution:</h3>

Given that It cost 5 dollars for a child ticket and 8 dollars for a adult ticket

cost of each child ticket = 5 dollars

cost of each adult ticket = 8 dollars

Let "c" be the number of child tickets bought

Let "a" be the number of adult tickets bought

Total tickets sold were 110 bringing in 820 dollars

Number of child tickets bought + number of adult tickets bought = 110

c + a = 110 ----- eqn 1

Also we can frame a equation as:

Number of child tickets bought x cost of each child ticket + number of adult tickets bought x cost of each adult ticket = 820

$c \times 5 + a \times 8 = 820$

5c + 8a = 820 -------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "c" and "a"

From eqn 1,

a = 110 - c ------ eqn 3

Substitute eqn 3 in eqn 2

5c + 8(110 - c) = 820

5c + 880 - 8c = 820

-3c = - 60

c = 20

Therefore from eqn 3,

a = 110 - 20 = 90

a = 90

Therefore number of child tickets bought is 20

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3 years ago

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Answer:

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Step-by-step explanation:

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Based on the 2009 season, the Texas Rangers have a winning percentage of .533. Use the binomial model to find the probability th

Naddik [55]

Answer:

0.128

Step-by-step explanation:

We know the probability for any event X is given by,

$P(X=x)=\binom{n}{x}\times p^{n-x}\times q^{x}$ ,

where p is the probability of success and q is the probability of failure.

Here, we are given that p = 0.533.

Since, we have that q = 1 - p

i.e. q = 1 - 0.533

i.e. q = 0.467

It is required to find the probability of 4 wins in the next 5 games i.e. P(X=4) when n = 5.

Substituting the values in the above formula, we get,

$P(X=4)=\binom{5}{4}\times 0.533^{5-4}\times 0.467^{4}$

i.e. $P(X=4)=5 \times 0.533 \times 0.048$

i.e. i.e. $P(X=4)=0.128$

Hence, the probability of 4 wins in the next 5 games is 0.128.

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3 years ago

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