Split up the interval [0, 2] into <em>n</em> equally spaced subintervals:
![\left[0,\dfrac2n\right],\left[\dfrac2n,\dfrac4n\right],\left[\dfrac4n,\dfrac6n\right],\ldots,\left[\dfrac{2(n-1)}n,2\right]](https://tex.z-dn.net/?f=%5Cleft%5B0%2C%5Cdfrac2n%5Cright%5D%2C%5Cleft%5B%5Cdfrac2n%2C%5Cdfrac4n%5Cright%5D%2C%5Cleft%5B%5Cdfrac4n%2C%5Cdfrac6n%5Cright%5D%2C%5Cldots%2C%5Cleft%5B%5Cdfrac%7B2%28n-1%29%7Dn%2C2%5Cright%5D)
Let's use the right endpoints as our sampling points; they are given by the arithmetic sequence,

where
. Each interval has length
.
At these sampling points, the function takes on values of

We approximate the integral with the Riemann sum:

Recall that

so that the sum reduces to

Take the limit as <em>n</em> approaches infinity, and the Riemann sum converges to the value of the integral:

Just to check:

Answer:
4x² -29x +51
Step-by-step explanation:
Put x-3 where x is in the original function definition, then "simplify". I think you'll find it convenient to rewrite the original function definition first.
... g(x) = 4x² -5x = x(4x -5)
Substituting, we have
... g(x-3) = (x -3)(4(x -3) -5)
... = (x -3)(4x -17) . . . . . simplify right factor
... = 4x² -12x -17x +51
... g(x -3) = 4x² -29x +51
Answer: 5:2
Thursday and Tuesday start with t
Monday, Wednesday, Friday, Saturday, and Sunday do not.
Step-by-step explanation:
Risk - 5 = 16. It is just mathematical language.
Answer:
A)6x-18, B)They are not equal, since 6xx18 is not equal to 6x-9
Step-by-step explanation:
2(3x-9) = 2(3x)-2(9) =6x-18.