Question

On a coordinate plane, a line goes through (negative 3, 2) and (2, negative 1). A point is at (3, 0). What is the equation of the line that is perpendicular to the given line and passes through the point (3, 0)

Answer 1

Answer:            $y=\frac{5}{3}x-5$

Step-by-step explanation:

Alright, lets get started.

Two points are given as (-3,2) and (2,-1)

Slope will be : $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Slope will be : $\frac{-1-2}{2-(-3)}$

Slope will be : $\frac{-3}{5}$

Our line is perpendicular to this slope, then,

$m \times (\frac{-3}{5}) =-1$

$m=\frac{5}{3}$

Line passing through the point (3,0) and having slope $\frac{5}{3}$, is given by :

$y-y_{1}=m(x-x_{1} )$

$y-0=\frac{5}{3}(x-3)$

$y=\frac{5}{3}x-5$    :  Answer

Hope it will help :)

Answer 2

Answer:

y=\frac{5}{3}x-5

Step-by-step explanation: