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Harrizon [31]
3 years ago
15

Need an explanation and answer for -25/28 ÷ (5/4)

Mathematics
1 answer:
lyudmila [28]3 years ago
5 0

Answer:

-5/7

Step-by-step explanation:

When you divide fractions, you flip the second fraction, then multiply.

So it becomes -25/28 x 4/5.

This equals -100/140 which reduces to -5/7.

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43 Sets for 650

Step-by-step explanation:

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3 years ago
Please help with 3. 4. 5.
Eddi Din [679]
3.
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4.
r-6+3r-3+5r=180\\9r-9=180\ \ \ |+9\\9r=189\ \ \ |:9\\r=21
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4 0
3 years ago
Can someone please help me and fast I'm stuck
vovikov84 [41]

Answer:

3 5/8

Step-by-step explanation:

6 4/8 - 2 7/8 = 4 -3/8 = 3 5/8

8 0
2 years ago
Read 2 more answers
Alyze the following special produ
Eddi Din [679]

Answer:

1) Solving the term (3x + 5)(2x - 3) using F.O.I.L we get \mathbf{6x^2+x-15}

2) solving the term (x + 2)(x - 13) using F.O.I.L we get \mathbf{x^2-11x-26}

3) Solving (x+5)^2 using square of binomial we get \mathbf{x^2+10x+25}

4) Solving (x+5)^2 using square of binomial we get \mathbf{x^2-6x+9}

Step-by-step explanation:

1) (3x + 5)(2x - 3). Solve using the F.O.I.L.

F.O.I.L stands for First, Outer Inner Last

We have (3x + 5)(2x - 3)

First: 3x(2x)

Outer: 3x(-3)

Inner: 5(2x)

Last: 5(-3)

Solving we get:

(3x + 5)(2x - 3)\\=3x(2x)+3x(-3)+5(2x)+5(-3)\\=6x^2-9x+10x-15\\=6x^2+x-15

So, solving the term (3x + 5)(2x - 3) using F.O.I.L we get \mathbf{6x^2+x-15}

2) (x + 2)(x – 13). Solve using the F.O.I.L.

F.O.I.L stands for First, Outer Inner Last

We have (x + 2)(x -13)

First: x(x)

Outer: x(-13)

Inner: 2(x)

Last: 2(-13)

Solving we get:

(x + 2)(x - 13)\\=x(x)+x(-13)+2(x)+2(-13)\\=x^2-13x+2x-26\\=x^2-11x-26

So, solving the term (x + 2)(x - 13) using F.O.I.L we get \mathbf{x^2-11x-26}

3) (x + 5)^2. Solve using the square of Binomial.

The square of binomial is: (a+b)^2=a^2+2ab+b^2

Solving:

(x+5)^2\\=(x)^2+2(x)(5)+(5)^2\\=x^2+10x+25

So, solving (x+5)^2 using square of binomial we get \mathbf{x^2+10x+25}

4) (x -3)^2. Solve using the square of Binomial.

The square of binomial used is: (a-b)^2=a^2-2ab+b^2

Solving:

(x-3)^2\\=(x)^2-2(x)(3)+(3)^2\\=x^2-6x+9

So, solving (x+5)^2 using square of binomial we get \mathbf{x^2-6x+9}

5 0
3 years ago
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Answer:

D

Step-by-step explanation:

6b+4r

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3 years ago
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