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3 years ago

14

3 000 000 000+200 000 000+600 000+20 000+9

2 answers:

Alex787 [66]3 years ago

7 0

320,062,000,9 is the answer

Leona [35]3 years ago

3 0

3200620009 is the answer to your question

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A boat leaves a.M. Marina at 7 AM traveling at 3.4 knots bearing is N38°E the boat docks on an island at 2pm how far north of th

Jlenok [28]

Answer:

The distance between the docks & island is 44.07 km.

Step-by-step explanation:

Speed of the boat S = 3.4 knot = 6.3 $\frac{km}{hr}$

Time taken by bot to reach the island = 7 hr

We know that the distance is given by

Distance = Speed × Time

Put all the values in above equation we get

D = 6.3 × 7

D = 44.07 km

Therefore the distance between the docks & island is 44.07 km.

6 0

3 years ago

In a particular month, Ezhil spent one-fifth of her salary on shopping. Two-fifth of the remaining she gave to her sister. If sh

Oxana [17]

Answer:

$Salary = Rs23000$

Step-by-step explanation:

Given

$Shopping = \frac{1}{5}$

$Sister = \frac{2}{5}R$

$Left over = Rs11,040$

Required

Her salary in that month

Given that she spent $\frac{1}{5}$ of her salary on shopping, this implies that she has $\frac{4}{5}$ of her salary left

From what's left, she gave her sister $\frac{2}{5}$

This means she gave her sister $\frac{2}{5} * \frac{4}{5}$

Sister = $\frac{8}{25}$

Calculating a fraction of what's left

$Left over = 1 -Shopping - Sister$

$Left over = 1 - \frac{1}{5}- \frac{8}{25}$

$Left over = \frac{25 - 5 - 8}{25}$

$Left over = \frac{12}{25}$

Recall that she has Rs11,040

This means that

$\frac{12}{25} of Salary = Rs11,040$

Multiply both sides by $\frac{25}{12}$

$\frac{12}{25} * \frac{25}{12} * Salary = Rs11,040 * \frac{25}{12}$

$Salary = Rs11,040 * \frac{25}{12}$

$Salary = \frac{Rs276000}{12}$

$Salary = Rs23000$

Hence, her salary for that month was Rs23000

5 0

3 years ago

Read 2 more answers

19. (3,5), (2,-2)

Viktor [21]

Answer:

y=7x−16 the answer ;)

8 0

3 years ago

Find the solution of the given initial value problems in explicit form. Determine the interval where the solutions are defined.

natali 33 [55]

Answer:

The solution of the given initial value problems in explicit form is $y=x-x^2-2$ and the solutions are defined for all real numbers.

Step-by-step explanation:

The given differential equation is

$y'=1-2x$

It can be written as

$\frac{dy}{dx}=1-2x$

Use variable separable method to solve this differential equation.

$dy=(1-2x)dx$

Integrate both the sides.

$\int dy=\int (1-2x)dx$

$y=x-2(\frac{x^2}{2})+C$ $[\because \int x^n=\frac{x^{n+1}}{n+1}]$

$y=x-x^2+C$ ... (1)

It is given that y(1) = -2. Substitute x=1 and y=-2 to find the value of C.

$-2=1-(1)^2+C$

$-2=1-1+C$

$-2=C$

The value of C is -2. Substitute C=-2 in equation (1).

$y=x-x^2-2$

Therefore the solution of the given initial value problems in explicit form is $y=x-x^2-2$ .

The solution is quadratic function, so it is defined for all real values.

Therefore the solutions are defined for all real numbers.

4 0

3 years ago

What’s the correct answer for this question?

Jobisdone [24]

Answer:

A.

Step-by-step explanation:

A quadrilateral inscribed in a circle has its opposite angles adding up to 180°

So

<NOP + <M = 180

4x+8x-24 = 180

12x = 180+24

12x = 204

Dividing both sides by 12

x = 17

<NOP = 4(17)

= 68°

8 0

3 years ago