Question:
Morgan is playing a board game that requires three standard dice to be thrown at one time. Each die has six sides, with one of the numbers 1 through 6 on each side. She has one throw of the dice left, and she needs a 17 to win the game. What is the probability that Morgan wins the game (order matters)?
Answer:
1/72
Step-by-step explanation:
<em>Morgan can roll a 17 in 3 different ways. The first way is if the first die comes up 5, the second die comes up 6, and the third die comes up 6. The second way is if the first die comes up 6, the second die comes up 5, and the third die comes up 6. The third way is if the first die comes up 6, the second die comes up 6, and the third die comes up 5. For each way, the probability of it occurring is 1/6 x 1/6 x 1/6 = 1/216. Therefore, since there are 3 different ways to roll a 17, the probability that Morgan rolls a 17 and wins the game is 1/216 + 1/216 + 1/216 = 3/216 = 1/72</em>
<em>I had this same question on my test!</em>
<em>Hope this helped! Good Luck! ~LILZ</em>
Answer:
24 hours
Step-by-step explanation:
set up a ratio:
12 miles = 16 hours
------------- ------------
18 miles = x hours
cross multiply
12m * x = 16h * 18 m
solve for x
x=16h * 18m / 12m = 24 hours
Answer:
48 and 48
Step-by-step explanation:
product means multiplication
two middle values are 3 and 16
3*16 = 48
two outside values are 2 and 24
2*24 = 48
Answer:
right
Step-by-step explanation:
The box in the lower corner means that the angle is equal to 90 degrees, which means the angle is a right angle
The triangle is a right triangle
