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3 years ago

What terms can be combined with a2?

Mathematics

2 answers:

Nata [24]3 years ago

6 0

Answer:

a + a= a2 :) :)

DaniilM [7]3 years ago

3 0

Answer:

a·2

Step-by-step explanation:

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I need help. See picture: "Number of solutions to equations challenge"

Zanzabum

Answer:

Step-by-step explanation:

Put the values of P and Q to the equation Px - 45 = Qx + 75:

15x - 45 = 15x + 75 subtract 15x from both sides

-45 = 75 FALSE

In other cases, we get some value x.

Example:

A. P = -45 and Q = -75

-45x - 45 = -75x + 75 add 45 to both sides

-45x = -75x + 120 add 75x to both sides

25x = 120 divide both sides by 25

x = 4.8

3 0

3 years ago

Solve this equation for x. 2/3(x+8)^2-66=0

yKpoI14uk [10]

Answer:

$\large\boxed{x=-8\pm3\sqrt{11}}$

Step-by-step explanation:

$\dfrac{2}{3}(x+8)^2-66=0\qquad\text{add 66 to both isdes}\\\\\dfrac{2}{3}(x+8)^2-66+66=0+66\\\\\dfrac{2}{3}(x+8)^2=66\qquad\text{multiply both sides by 3}\\\\3\!\!\!\!\diagup^1\cdot\dfrac{2}{3\!\!\!\!\diagup_1}(x+8)^2=(3)(66)\\\\2(x+8)^2=198\qquad\text{divide both sides by 2}\\\\\dfrac{2\!\!\!\!\diagup^1(x+8)^2}{2\!\!\!\!\diagup_1}=\dfrac{198\!\!\!\!\!\diagup^{99}}{2\!\!\!\!\diagup_1}\\\\(x+8)^2=99\iff x+8=\pm\sqrt{99}\qquad\text{subtract 8 from both sides}$

$x+8-8=-8\pm\sqrt{(9)(11)}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\x=-8\pm\sqrt9\cdot\sqrt{11}\\\\x=-8\pm3\sqrt{11}$

8 0

4 years ago

A pet store has 45 mice. The number of mice is 22 more than the number of cats. Which equation can be solved to find the number

Lemur [1.5K]

Answer:

c+22=45

Step-by-step explanation:

It is the answer

4 0

3 years ago

Which of the following shows that △ABD≅△CBD, when y=5?

Pavlova-9 [17]

Answer:

The correct option is;

∠ADB ≅ ∠CDB, $\overline {BD}$ ≅ $\overline {BD}$ and $\overline {AD}$ ≅ $\overline {CD}$ . So ΔABD ≅ ΔCDB by SAS

Step-by-step explanation:

The given parameters are;

The polygon given = Quadrilateral

The diagonal of the quadrilateral = BD

The length of the side AD = (2×y + 5) units

The length of the side CD = (y + 10) units

The given measure of ∠ABD = (2 × y + 25)°

The given measure of ∠CBD = 35°

When y = 5, we have by substituting the value of y into the equations representing the dimensions of the quadrilateral ABCD;

The length of the side AD = 2 × y + 5 = 2×5 + 5 = 15 units

∴ The length of the side AD = 15 units

The length of the side CD = (y + 10) units = (5 + 10) units = 15 units

∴ The length of the side CD = 15 units

The measure of ∠ABD = (2 × y + 25)° = (2 × 5 + 25)° = 35°

The measure of ∠ABD = 35°

Therefore;

∠ADB ≅ ∠CDB by substitution

$\overline {BD}$ ≅ $\overline {BD}$ by reflexive property

$\overline {AD}$ ≅ $\overline {CD}$ by substitution

∴ ΔABD ≅ ΔCBD by Side-Angle-Side rule of congruency

7 0

3 years ago

1/6x+42+2/5x-8/3x-19=

DochEvi [55]

(x/6) + 42 + (2x/5) - (8x/3) - 19

Change the denominators (numbers below the fraction bar to a to a common number for the three numbers: 6, 5, and 3... in other words to a number that is divisible by all three numbers)

(5x/30) + (12x/30) - (80x/30) + 23
(-63x/30) + 23

And the answer is.....

(-21x/10) + 23

5 0

4 years ago