3 years ago

Find the 31st term of the following sequence. 9, 15, 21, ...

1 answer:

8 0

The 31st term of this sequence is 189.
9, 15, 21, 27, 33 (5), 39, 45, 51, 57, 63 (10), 69, 75, 81, 87, 93 (15), 99, 105, 111, 117, 123 (20), 129, 135, 141, 147, 153 (25), 159, 165, 171, 177, 183 (30), 189.

You might be interested in

If a = 3, what is the value of the expression 36 ÷ a · 4 + 2? <br> 5 <br> 48 <br> 50 <br> 72

amm1812

50. Plug in 3 for a and divide that by 36

7 0

3 years ago

Read 2 more answers

Does anybody know? Find the value of x in the regular polygon

Gala2k [10]

That is a dodecagon, so x without context is 150.

6 0

1 year ago

Read 2 more answers

Identify the zeros for the function and sketch a graph. y=x(x-2)(x+3)

damaskus [11]

The product is equal to zero if one of the factors is equal to zero.

Therefore:

$y=x(x-2)(x+3)\\\\x(x-2)(x+3)=0\iff x=0\ \vee\ x-2=0\ \vee\ x+3=0\\\\\boxed{x=0\ \vee\ x=2\ \vee\ x=-3}$

5 0

3 years ago

Frodo and Sam are photographers. They take pictures of seniors for high school yearbooks. They charge a standard fee for taking

liubo4ka [24]

(0,15)(1,19)
slope = (19 - 15) / (1 - 0) = 4

y = mx + b
slope(m) = 4
(0,15)...x = 0 and y = 15
sub
15 = 4(0) + b
15 = b

y = 4x + 15....so ur rule is : F(s) = 4s + 15

7 0

3 years ago

Frank has a student loan of $55,780.

LenaWriter [7]

Answer: $6197.77 would be the right answer

hope it helps :]

7 0

2 years ago