1. Using c=2pi(r), plug in 7 for r and solve. Then using a=pi(r)^2, plug in 7 for r once again and solve.
2. First, the diameter (d) is 12 so to get the radius (r), divide 12 by 2 and you should get 6. Then use c=2pi(r) for circumference and a=pi(r)^2 for area to solve.
3. To get the area of the semicircle, divide 16 by 2 to get the radius (r), plug it into a=pi(r)^2, and divide the answer you get for a by 2. To get the area of the triangle, use a=1/2bh, plugging in 16 for b and 10 for h. Finally, add your two answers (the a's from the semicircle and triangle problems).
4. Multiply 20 by 5.5 to get the area of the triangle. Then multiply 4.5 by 20 to get the area of the parallelogram and add your two quotients.
5. Use a=1/2bh and plug in 4 for b and 3 for h and solve. Then multiply the quotient by 10 and there's your volume. To find the surface area, solve SA=(10×4)+(10×3)+(10×5)+12. All I did there was find the area of all the sides and added them together.
6. To find the triangle's volume, use a=1/2bh (b=4, h=1.5) and then multiply the quotient of that by 2.5. To find the rectangle's volume, use v=lwh (l=4, w=2.5, h=2) and solve. Finally, add the triangle's volume and the rectangle's volume to get the total volume. To get its surface area, start with the rectangle. Find the areas of all the sides and add them together but then subtract the 2.5×4 rectangle as it is not on the surface. It should look like this: SA=2(4×2)+2(2.5×2)+10. Again, all I did was find the areas of all the rectangle's sides on the surface and added them. Next, find the triangle's areas on the surface and it should look like this: SA=2(1.5×4)+2(2.5×2.5). Finally, add both values of SA from the triangle and rectangle and there's your surface area.
In these types of problems, the first step is to combine like terms. Like terms are terms with the same exponent (power), and the same variable (like all x's). In the above equation, we can combine -5x, 2x and -3y. Let's do it:
The next step would be to factor out the common ratio, which is not applicable here, so your answer would be
-6x + 7y. Hope this helps!
A- 2b = 2 one of the 2 "A" most be negative so they can cancer each other
-a- b = 6 after the "A" cancel each other add the -2b with -b = -3b, then add 2
-------------- and 6
-3b=8 then you have to divide 8 by -3 = -2.6 -2.6 its b... now you have to solve for b step 1. a -2b = 2 step 2. a -2(-2.6)=2 step 3 a -5.3 = 2 then subtract -5.3 with 2 so that going to be 2 + 5.3 =7.3 then divide by a
final answer (-2.5,-7.3)
sorry its kinda hard to explained here, i hope you get the point :)
Answer: The answer is ∠TUV.
Step-by-step explanation: Given in the question a quadrilateral SVUT with ∠SVU = 112°. We need to determine the angle whose measure will decide whether or not the quadrilateral SVUT is a trapezoid.
We know that for a quadrilateral to be a trapezoid, we need only one condition that one pair of opposite sides must be parallel.
So, in quadrilateral SVUT, since the measure of ∠SVU is given, so we can decide it is a trapezoid or not if we know the measure of ∠TUV. As ST and UV cannot be parallel, so its meaningless to determine ∠TSV.
For SV and TU to be parallel to each other, we need
∠SVU + ∠TUV = 180° (sum of interior alternate angles).
Therefore,
∠TUV = 180° - 112° = 68°.
Thus, we need to determine ∠TUV and its measure shoul be 68°.
Answer:
see explanation
Step-by-step explanation:
In a rectangle
• All angles are right angles
• the diagonals are congruent
In Δ WXV the sum of the 3 angles = 180°
∠ WXZ = ∠ XWY = 
= 
= 58°
∠ YXZ = 90° - 58° = 32°
∠ WVZ = 180° - 64° = 116° ( adjacent angles are supplementary )
∠ XWZ = 90° ( by definition of rectangle )
∠ XZY = ∠ WXZ = 58° ( corresponding angles )
