Ask question

Ask question

All categories

2 years ago

7

The height of a mountain is 6,384 meters. What is its height in millimeters? 6,384,000 mm 638,400 mm 63.84 mm 6.384 mm

2 answers:

docker41 [41]2 years ago

5 0

Answer:

The answer is 6,384,000.

Step-by-step explanation:

1 meter = 1,000 millimeters. So to find the height of the mountain in millimeters you have to multiply it by 1,000. Giving you the answer 6,384,000.

Karo-lina-s [1.5K]2 years ago

3 0

The answer is 6,384,000 mm

You might be interested in

4 x (-4) dived by (2) - (-3) + (-6)

spayn [35]

Answer: the answer that i got was -11

4 0

2 years ago

an outlier may be defined as a data point that is more than 1.5 times the interquartile range below the lower quartile or is mor

Ira Lisetskai [31]

Supposing a normal distribution, we find that:

The diameter of the smallest tree that is an outlier is of 16.36 inches.

--------------------------------

We suppose that tree diameters are normally distributed with <u>mean 8.8 inches and standard deviation 2.8 inches.</u>

<u />

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.<u> </u>

<u />

In this problem:

Mean of 8.8 inches, thus $\mu = 8.8$ .
Standard deviation of 2.8 inches, thus $\sigma = 2.8$ .

<u />

The interquartile range(IQR) is the difference between the 75th and the 25th percentile.

<u />

25th percentile:

X when Z has a p-value of 0.25, so X when Z = -0.675.

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 8.8}{2.8}$

$X - 8.8 = -0.675(2.8)$

$X = 6.91$

75th percentile:

X when Z has a p-value of 0.75, so X when Z = 0.675.

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 8.8}{2.8}$

$X - 8.8 = 0.675(2.8)$

$X = 10.69$

The IQR is:

$IQR = 10.69 - 6.91 = 3.78$

What is the diameter, in inches, of the smallest tree that is an outlier?

The diameter is <u>1.5IQR above the 75th percentile</u>, thus:

$10.69 + 1.5(3.78) = 16.36$

The diameter of the smallest tree that is an outlier is of 16.36 inches.

<u />

A similar problem is given at brainly.com/question/15683591

3 0

1 year ago

Joanna needs a book to prop up a table leg. She randomly selects a book , and selects another book . What is probability that sh

Stolb23 [73]

Id say 40%
because 8 are math so 9 of them are other

3 0

2 years ago

he U.S. Bureau of Labor Statistics reports that the average annual expenditure on food and drink for all families is $5700. Assu

Papessa [141]

Answer:

87.08% percentage of families spend more than $4000 annually on food and drink

Step-by-step explanation:

Given -

average annual expenditure on food and drink for all families is $5700

Mean $(\nu)$ = 5700

standard deviation $(\sigma )$ = 1500

Let X be the no of families spend annually on food and drink

percentage of families spend more than $4000 annually on food and drink =

$P(X > 4000)$ = $P(\frac{X - \nu }{\sigma }> \frac{ 4000 - 5700}{1500})$

= $P(Z > - 1.13)$ Using $(Z = \frac{X - \nu }{\sigma })$

= 1 - $P(Z$

= 1 - .1292

= .8708

= 87.08%

7 0

3 years ago

Height versus age.

LenaWriter [7]

So basically the height is divided by a certain number to evenly divide it

8 0

2 years ago