Answer:
For first lamp ; The resultant probability is 0.703
For both lamps; The resultant probability is 0.3614
Step-by-step explanation:
Let X be the lifetime hours of two bulbs
X∼exp(1/1400)
f(x)=1/1400e−1/1400x
P(X<x)=1−e−1/1400x
X∼exp(1/1400)
f(x)=1/1400 e−1/1400x
P(X<x)=1−e−1/1400x
The probability that both of the lamp bulbs fail within 1700 hours is calculated below,
P(X≤1700)=1−e−1/1400×1700
=1−e−1.21=0.703
The resultant probability is 0.703
Let Y be a lifetime of another lamp two bulbs
Then the Z = X + Y will follow gamma distribution that is,
X+Y=Z∼gamma(2,1/1400)
2λZ∼
X+Y=Z∼gamma(2,1/1400)
2λZ∼χ2α2
The probability that both of the lamp bulbs fail within a total of 1700 hours is calculated below,
P(Z≤1700)=P(1/700Z≤1.67)=
P(χ24≤1.67)=0.3614
The resultant probability is 0.3614
2m^4
So basically choose B. You basically had to find the prime factors of each term in order to find the GCF
7,5
these two are the ones for prime numbers between 7 and 35
Answer:
1.0 g element will be remaining after 19 minutes
Step-by-step explanation:
Answer:
2 1/2 rolls
Step-by-step explanation:
rolls : walls = (1/2) : (1/10) = ? : (1/2) = 5/2 : 1/2 (multiply by 5, since 1/2 = 5/10)
It takes 5/2 rolls = 2 1/2 rolls to cover half the wall.
