2 years ago

Factor completely. 49 t6 - 4 k8

Mathematics

1 answer:

krek1111 [17]2 years ago

7 0

49 t^6 - 4 k^8
= (7t^3)^2 - (2k^4)^2
= (7t^3 + 2k^4)(7t^3 - 2k^4)

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