$\bf \textit{difference and sum of cubes}
\\\\
a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad
(a+b)(a^2-ab+b^2)= a^3+b^3 
\\\\
a^3-b^3 = (a-b)(a^2+ab+b^2)\qquad
(a-b)(a^2+ab+b^2)= a^3-b^3\\\\
-------------------------------\\\\
64g^3+8\implies 4^3g^3+8\implies (4g)^3+2^3
\\\\\\
(4g+2)[(4g)^2-(4g)(2)+2^2]\implies (4g+2)[(4^2g^2)-8g+4]
\\\\\\
(4g+2)(16g^2-8g+4)$

3 0

3 years ago

which of the following is the equation of the line that passes though the point (-2,1) and has a slope of 4

Ierofanga [76]

An equation that goes through (-2, 1) and has a slope of 4 is y = 4x + 9.

You can find this by looking for the y-intercept (b) by using the slope (m), the point and slope intercept form. The work is below for you.

y = mx + b

1 = 4(-2) + b

1 = -8 + b

9 = b

Now we can use that and the slope to create the equation y = 4x + 9

4 0

3 years ago