Answer:
there are 45 people in the group
2/3xA=30
2A=30x3
A=90/2
A=45
Answer:
The answer is -2c - 4w
Step-by-step explanation:
You have to combine the c's and the w's and you get -2c and -4w
<h2>Greetings!</h2>
A)
<h3>If you can see, every 4 minutes the amount of water is increasing at a constant rate. </h3>
197 - 153 = 44
285 - 241 = 44
<h3>This means that at 8 minutes, because there is 153 gallons already in, we can divide 8 by 4 to see how many groups of 4 minutes there were. </h3>
8 ÷ 4 = 2
So then we can subtract two lots of 44 from 153:
153 - (44 x 2) = 65
<h3>So the starting amount was 65.</h3>
B)
<h3>The answer to B is the second option, because it is true that the amount of water is increasing. This is by 44 gallons per 4 minutes.</h3>
The amount of gallons per minute can be found out by dividing the amount by 4:
44 ÷ 4 = 11
<h3>So it is 11 gallons per minute.</h3>
<h2>Hope this helps!</h2>
if ya asking for simpliicatio
remember that 
and


factor




S= Sydney
devaughn= s-13
so s+s-13=75
2s-13=75
now I think you can solve the rest.