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kipiarov [429]
3 years ago
13

Solve the system using the method of your choice: y = 3x – 4 2x + 4y = 26 SHOW WORK

Mathematics
1 answer:
SVEN [57.7K]3 years ago
8 0

Hello Savanna


y=3x-4

2x+4y=26

Can we solve it together ? :) Thx


We need to solve y=3x-4 for y

Now let's start solving this by substitute 3x-4 for y in 2x+4y=26

2x+4(3x-4)=26

14x-16=26

Now let's add 16 to both sides

14x-16+16=26+16

14x=42

Divide both sides by 14 so we can find the value for x

14x/14= 42/14

x=3

Good job:) now we find the value of x

We are not done yet.


Let's find the value for y by substitute 3 for x in y=3x-4

y=3x-4

y=(3)(3)-4

y=9-4

y=5

Yeah well done :)

Final answer : x=3 and y=5

                         (3,5)


Was that helped ? please rate my answer :0


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jayson is installing nee flooring in his home if the lenght of the room is 26 feet and the width is 6 feet how many sq feet of f
user100 [1]
The equation for area is length * width = area. 
With that said put your numbers into the equation. 
You get: 
26*6=?
Then you will have your answer. 
If you do not know how to do 26*6 do this:
6*6=x
20*6=y
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Hope this helps :)

5 0
3 years ago
Juan has 6 times as many baseball cards as Nick. If Juan has 192 cards, how many does Nick have?
inessss [21]
<h3>Answer:</h3>

32

<h3>Step-by-step explanation:</h3>

Divide 192 by 6, to find the amount of baseball cards Nick has.

192 ÷ 6 = <u>32</u>

<h3><u>Check:</u></h3>

32 · 6 = 192

192 ÷ 6 = 32

Nick has 32 baseball cards, which is 6 times less than Juan's amount.

7 0
3 years ago
Write the number equal to 7 tens and 3 ones
kaheart [24]
The answer would be 73
7 0
3 years ago
Read 2 more answers
PLS HELP I DONT UNDERSTAND!!<br> What type of circle would you use when graphing x≥5
inna [77]

How to:

When graphing a linear inequality on a number line, use an open circle for "less than" or "greater than", and a closed circle for "less than or equal to" or "greater than or equal to".

For this problem:

For the number line, we would place a solid dot at −5 because the value is both greater than and equal too (≥) and then continue a line on the number line to the right of that point incorporating all values greater than −5

Answer:

<em><u>(image attached) </u></em>

<em><u>Look at the one showing your problem, the first one.</u></em>

<em><u>It's reverse of that since X is greater meaning the line goes the other way instead as shown in the second image.</u></em>

I HOPE I HELPED!! HAVE AN AMAZING DAY/NIGHT!!! PLEASE GIVE MY BRAINLIEST IF I HELPED YOU!!!!

-Sorry if I was unable to help you....I did my best!!

5 0
3 years ago
1In a card game, there are 49 cards, 7 of each color of the rainbow (red, orange, yellow, green, blue, indigo,violet). The cards
bogdanovich [222]

Answer:

Step-by-step explanation:

a) No two cards should be of the same colour. So for each of the seven cards we have to choose them from different colours. And for each colour we have 7 cards.

So for the required selection: We first select a card from one particular colour in 7C1 = 7 ways. Then we select the second card for the hand from one of the rest of the colours in 7C1 = 7 ways again as the other colour also has 7 cards. And so on.

So no. of ways in which we have a hand of no two cards to be same = 7 x 7 x 7 x 7 x 7 x 7 x 7 = 7^7 = 8,23,543

b) There are 7 cards numbered 4 each of the 7 rainbow colours. Apart from those we have 42 cards from which we have to choose a hand of 7 thus ensuring that there are no cards numbered 4. So we have to select 7 cards out of 42 which can be done in 42C7 = (42!) / 7!35! = 2,69,78,328

c) There are 3 even numbered cards of each colour:(2,4,6) So a total of 21 even numbered cards and rest 28 odd numbered cards. We can choose 4 even numbered cards out of 21 of them in 21C4 = (21!)/(4!17!) = 5,985 ways

And we can choose 3 odd numbered cards out of 28 of them in 28C3 = (28!)/(3!25!) = 3,276 ways

So number of hands with 4 even and 3 odd numbers = 5985 x 3276 = 1,96,06,860

d) Consider that we have two particular colors of which we want the hand of 7 cards to be made of. For the two colors we get a total of 14 cards. We can select 7 out of these 14 cards in 14C7 = 3,432 ways.

But out of these 3432 ways there are two ways which are not desirable. That is when all seven cards are of either one of the two colors. Because then the criteria that the hand is made of exactly two colors will be violated. Hence we remove those two cases so 3430 ways for any two particular colors.

Now out of the 7 colors we can choose any two in 7C2 = 21 ways

So total number of hands made up of exactly two colors = 21 x 3430 = 72,030

6 0
3 years ago
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