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3 years ago

If 4 books equals to 5 months how many books equals 15 months

Mathematics

1 answer:

Murrr4er [49]3 years ago

8 0

Answer:

12 months

Step-by-step explanation:

Based on the question

4 books equals to 5 months

x books equals to 15months

To determine the value of X we will have to cross multiply,it means

5x=15×4

5x=60

Divide both sides by 5

x=12

Therefore,x=12

Which means 12 books equals to 12 months

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Show answer in lowest terms. 3 1 /4 - 1 3/16=

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3 years ago

A hoop, a uniform solid cylinder, a spherical shell, and a uniform solid sphere are released from rest at the top of an incline.

Serjik [45]

Answer:

Step-by-step explanation:

Given

Hoop, Uniform Solid Cylinder, Spherical shell and a uniform Solid sphere released from Rest from same height

Suppose they have same mass and radius

time Period is given by

$t=\sqrt{\frac{2h}{a}}$ ,where h=height of release

a=acceleration

$a=\frac{g\sin \theta }{1+\frac{I}{mr^2}}$

Where I=moment of inertia

a for hoop

$a=\frac{g\sin \theta }{1+\frac{mr^2}{mr^2}}$

$a=\frac{g\sin \theta }{2}$

a for Uniform solid cylinder

$a=\frac{g\sin \theta }{1+\frac{mr^2}{2mr^2}}$

$a=\frac{2g\sin \theta }{3}$

a for spherical shell

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{3mr^2}}$

$a=\frac{3g\sin \theta }{5}$

a for Uniform Solid

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{5mr^2}}$

$a=\frac{5g\sin \theta }{7}$

time taken will be inversely proportional to the square root of acceleration

$t_1=k\sqrt{2}=1.414k$

$t_2=k\sqrt{\frac{3}{2}}=1.224k$

$t_3=k\sqrt{\frac{5}{3}}=1.2909k$

$t_4=k\sqrt{\frac{7}{5}}=1.183k$

thus first one to reach is Solid Sphere

second is Uniform solid cylinder

third is Spherical Shell

Fourth is hoop

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3 years ago

What is the simplest form of 4 square root 81x^8y^5?

olasank [31]

Firstly,
thanks for posting this.

81 = 9x9 or 9 squared so at this stage I'm guessing the last two.
x^ 8 = (x^ 4) x (x^ 2) (its called the multiplication rule of indices).
Okay I have approx 14 mins to answer.
No panic
√ 81.x^8 x √ y^5
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did I just gain time?
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or 2 . √ 3x^3. √ y^5
more time
okay, so that wasnt successful.
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