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cestrela7 [59]
4 years ago
5

Determine the logarithmic regression of the data below using either a calculator or spreadsheet program. Then, estimate the x−va

lue when the y−value is 5.2. Round your answer to one decimal place. (4.7,10.7),(7.8,20.6),(10.5,30.2),(15.6,41),(20.8,56.1),(22,65.1). Please help right away! Thank you so much!

Mathematics
1 answer:
Lelu [443]4 years ago
3 0

Answer:

  • y ≈ 33.7·ln(x) -45.9
  • 4.6

Step-by-step explanation:

A graphing calculator can perform logarithmic regression, as can a spreadsheet. The least-squares best fit log curve is about ...

  y ≈ 33.7·ln(x) -45.9

The value of x estimated to make y = 5.2 is about 4.6.

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HELP ME PLEASE!!! A Kite flying in the air has a 12 feet line attached to it. It's line is pulled and cast an 11 feet shadow. Fi
ZanzabumX [31]

Step-by-step explanation:

By Pythagoras' theorem,

12^2 = 11^2 + height^2

height = ±√12^2 - 11^2 (rej -ve value since height > 0)

height = 16.279 (5sf) = 16.3 (nearest tenth place)

Topic: Pythagoras theorem

If you like to venture further, do check out my insta (learntionary) where I regularly post useful math tips! Thank you!

5 0
3 years ago
If postage costs $.54 for the first ounce and $.22 for the each additional ounce, calculate the cost of mailing a 10- ounce enve
sweet-ann [11.9K]

Answer:

Hence, the total cost of mailing 10 ounces is:

$ 2.52

Step-by-step explanation:

If postage costs $.54 for the first ounce and $.22 for the each additional ounce.

i.e. cost of first ounce=$ 0.54.

Now let x denote the number of ounces after the first ounce,

Hence, the cost of x ounces=$ (0.22×x)=$ 0.22 x

Hence, the cost of mailing (x+1) ounces is: $ (0.54+0.22 x)

Now, we have to find the cost of  mailing a 10- ounce envelope.

i.e. after the first ounce we need 9 more ounces.

Hence, the total cost of mailing is calculated as:

=$ (0.54+0.22\times 9)\\\\=$ (0.54+1.98)\\\\=$ 2.52\\

Hence, cost of mailing 10 ounces is:

$ 2.52

8 0
4 years ago
Read 2 more answers
The weight of baby goats is believed to be Normally distributed, with a mean of 5.75 pounds. The average weight of a random samp
Julli [10]

Answer:

The standard error of the mean is 0.0783.

Step-by-step explanation:

The Central Limit Theorem helps us find the standard error of the mean:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

The standard deviation of the sample is the same as the standard error of the mean. So

SE_{M} = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\sigma = 0.35, n = 20

So

SE_{M} = \frac{\sigma}{\sqrt{n}}

SE_{M} = \frac{0.35}{\sqrt{20}}

SE_{M} = 0.0783

The standard error of the mean is 0.0783.

7 0
3 years ago
The coordinates of the endpoints of AB and CD are A(2,
Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

m= \frac{y_2-y_1}{x_2-x_1}

Formula to Find Distance between two points

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

mAB ( represents , Slope of AB )

1. mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}

2. mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}

3. mCD=\frac{5-2}{6-5}=\frac{3}{1}=3

4. AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

5. BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

mAC = mBC  , and C is common point , hence these three are collinear points  making a straight line whole slope is -\frac{1}{3}

mAB=-\frac{1}{3}

mCD=3

mAB \times mCD = -\frac{1}{3} \times 3 = -1

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0
3 years ago
Solve the system of equations algebraically. Show all of your steps
Katyanochek1 [597]
I am going to explain this using the substitution method, considering it appears to be the best in this situation.

We know (from the bottom equation) that y can equal 3x+20. Using this knowledge, we substitute the y in the top equation for 3x+20. Now, we have an equation that looks like this:

3x+20=x^2+2x

Now we need to move x to one side and then do some radicals (square roots).
Subtract the 2x on the right (since it is smaller, negatives = NONONO), which will give you

x+20=x^2

Now, we take the square root of both sides to get

rad(x+20)=x

Now we have to simplify. 20 doesn't have a square root, but 4 goes into 20, and 4 has a square root of 2. This now becomes

2rad(x+5)

This doesn't simplify any further... we have a problem... no way to isolate x as far as my knowledge goes... Sorry, can't help you any further than that, but another person or your teacher might be able to. R.I.P...
4 0
3 years ago
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