I fear that there is an error copying your assignment.
65% of the students walked. Are all of the other students on buses? Are there both public buses AND private buses?
Assuming that you need to know BOTH kinds of buses, try this:
65% of the students walked, so since 100% - 65% = 35% then this means that 35% of the students were on buses.
Since we know that there are 360 more walkers than bus riders, then one equation we know is: 65% of S = 360 + 35% of S (let S = total # of students)
.65 S = 360 + .35 S
<u> - .35 S </u> = <u> - .35 S</u> Subtract .35 S from both sides
<u> .30 S </u> = <u> 360</u> Divide both sides by .30 (or .3)
.30 .30
S = 1,200 so we know that this is the total number of students, but that is not what was asked.
They want to know how many are on buses and specifically how many are on public buses, if I read this correctly.
Since the walkers = 65% of 1,2000 and we know of means TIMES, then
.65 (1,200) = 780 walkers
1,200 total students minus 780 walkers = 420 bus riders
Now, if there is not a misprint and we really have to figure out the public bus riders as compared to the private bus riders, then remember the ratio from above in the question: 4 bus: 3 public buses
Now if I read this right, that means that 3/4ths of the bus riders were on public buses
so 3/4 of 420 means 3/4 times 420 = 3 times 105 = 315 public bus riders (which coincidentally leaves 105 private bus riders, but since they are private we don't know much about them. Ha-Ha..... I made a lame joke.)
So your answer is 315 public bus riders
Answer:
Josh had $500
Karen had $100
Step-by-step explanation:
J = 5K
J - 20 = 6(K - 20)
5K - 20 = 6K - 120
100 = K
J = 500
7a
TSA = 2lw<span> + 2</span>lh<span> + 2</span><span>wh
TSA = 140 + 70 + 100 = 310 ft^2
7b
310 x $4 =$1240
cost = </span>$1240
7c
V= wlh = <span>7×10×5 = </span><span>350 ft^3</span>
Answer:
- The solution is (x, y) = (-2, 0)
- A graph is attached
Step-by-step explanation:
The graph shows the solution. The first equation has a y-intercept of -4 and a slope of -2, so will go through the point (-2, 0).
The second equation has a y-intercept of +4 and a slope of 2, so will go through the point (-2, 0).
Both equations have the same x-intercept, so that x-intercept is the solution to the system of equations.
Let's assume the some number be h.
Now the given statement is "seven less than some number".
Which means we need to take out 7 from h. Hence, it can be translate into an algebraic expression as h-7.
