Let us say that y = vertical height and z =
hypotenuse <span>
dz/dt = 600
dy/dt = 0 since y (altitude) is constant
sin(θ) = 2/3
Calculating for the angle: θ = arcsin(2/3) = 0.729728 radians
sin(θ) = y/z
z sin(θ) = y
<span>We then differentiate the two sides with respect to time t:
dz/dt sin(θ)+ z cos(θ) dθ/dt = dy/dt
(600) (2/3) + (3) cos (0.729728) dθ/dt = 0
400 + [3 / cos (0.729728) ] dθ/dt = 0
400+ 4.0249 dθ/dt = 0
dθ/dt = -98.38 radians/hour
= -99.38/60 radians / min
= -1.66 radians / min = 2PI - 1.66 radians / min
<span>= 4.62 radians / min (ANSWER)</span></span></span>
Answer:
yes that correct
Step-by-step explanation:
Answer:
13.5
Step-by-step explanation:
your teacher wrote all the tools you need down already.
we only need to apply them.
is that really so difficult ?
because of the law of sines we have
sin(27)/11 = sin(34)/x
we can also turn this upside down to simplify the calculation.
11/sin(27) = x/sin(34)
x = 11×sin(34)/sin(27) = 13.549 ≈ 13.5
there, that was all there was to it ...
Domain: all real numbers
Range: y>-3
Simply 3*2=6
6-17x-28
-17x+(6-28)
Answer : -17x-22