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Ksenya-84 [330]
4 years ago
6

ASAP ANSWER WITH WORK

Mathematics
1 answer:
ki77a [65]4 years ago
8 0

Answer:

21.2 or 21 1/5

Step-by-step explanation:

26 1/2 = 26.5

1 1/4 = 1.25

26.5/1.25 = 21.2

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Find the quotient: 15x^4y^2-30x^2y^3+45xy/5xy is ________. when this quotient is divided by _____the result is x^3y-2xy^2+3
gogolik [260]

\dfrac{15x^4y^2-30x^2y^3+45xy}{5xy}=\dfrac{15x^4y^2}{5xy}-\dfrac{30x^2y^3}{5xy}+\dfrac{45xy}{5xy}\\\\=3x^{4-1}y^{2-1}-6x^{2-1}y^{3-1}+9=3x^3y-6xy^2+9\\\\=3(x^3y-2xy^2+3)\\\\Used:\\\\\dfrac{a^n}{a^m}=a^{n-m}\\\\Answer:\\....\underline{3x^3y-6xy^2+9}...\ \ \ ...\underline{3}...

5 0
3 years ago
According to the rational root theorem, which statement about f(x)=66x^4-2x^3+11x^2+35 is true?
andrezito [222]

Answer:

Option (1)

Step-by-step explanation:

If a polynomial is given in the form of f(x) = ax³ + bx² + c

By rational root theorem rational roots of the given polynomial will be,

x = \frac{\pm \text{Factors of c}}{\pm \text{Factors of a}}

Given polynomial in the question is,

f(x) = 66x⁴- 2x³ + 11x²+ 35

Possible rational roots will be,

x = \frac{\pm \text{factor of 35}}{\pm \text{Facors of 66}}

Therefore, Option (1) will be the answer.

5 0
3 years ago
The radius of a circle is 5 feet. What is the angle measure of an arc bounding a sector with area 10​ square feet
Sonbull [250]

Answer:

nmm

Step-by-step explanation:

m,bnmm

4 0
4 years ago
A space is totally disconnected if its connected spaces are one-point-sets.Show that a finite Hausdorff space is totally disconn
marysya [2.9K]

Step-by-step explanation:

If X is a finite Hausdorff space then every two points of X can be separated by open neighborhoods. Say the points of X are x_1, x_2, ..., x_n. So there are disjoint open neighborhoods U_{12} and U_2, of x_1 and x_2 respectively (that's the definition of Hausdorff space). There are also open disjoint neighborhoods U_{13} and U_3 of x_1 and x_3 respectively, and disjoint open neighborhoods U_{14} and U_4 of x_1 and x_4, and so on, all the way to disjoint open neighborhoods U_{1n}, and U_n of x_1 and x_n respectively. So U=U_2 \cup U_3 \cup ... \cup U_n has every element of X in it, except for x_1. Since U is union of open sets, it is open, and so U^c, which is the singleton \{ x_1\}, is closed. Therefore every singleton is closed.

Now, remember finite union of closed sets is closed, so \{ x_2\} \cup \{ x_3\} \cup ... \cup \{ x_n\} is closed, and so its complemented, which is \{ x_1\} is open. Therefore every singleton is also open.

That means any two points of X belong to different connected components (since we can express X as the union of the open sets \{ x_1\} \cup \{ x_2,...,x_n\}, so that x_1 is in a different connected component than x_2,...,x_n, and same could be done with any x_i), and so each point is in its own connected component. And so the space is totally disconnected.

4 0
4 years ago
If h = 13 units and r = 6 units, then what is the volume of the cone shown above?
Darina [25.2K]
The equation for a cone is
V=(1/3)hpir^2

if pi=aprox 3.14 for this quesiton
and r=6 and h=13


V=(1/3)(13)(3.14)(6^2)
V=(1/3)(13)(3.14)(36)
V=(13)(3.14)(12)
V=(3.14)(156)
V=489.84 cubic units

4 0
3 years ago
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