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3 years ago

It would help a lot, and if able, please explain

Mathematics

2 answers:

Zigmanuir [339]3 years ago

4 0

The area of A square is side times side. Since all the sides of A square are equal, simply find the square root of 240.25 and you will receive 15.5 as your answer.

Ksju [112]3 years ago

3 0

Let one side of the square be x
all sides of the square are equal
A=x•x(area formula of a square)
240.25 = x^2
so then the lengths of the sides of the square is 15.5 in

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A cylinder soup has a radius of 1,6 in and is 5/7 in. tall what is the volume

nata0808 [166]

Answer:

$V=0.0623\ inch^3$

Step-by-step explanation:

Given that,

The radius of cylinder, r = 1/6 inch

The height of the cylinder, h = 5/7 inch

We need to find the volume of the cylinder. The formula for the volume of a cylinder is given by :

$V=\pi r^2 h\\\\=3.14\times (\dfrac{1}{6})^2\times \dfrac{5}{7}\\\\V=0.0623\ inch^3$

So, the volume of the cylinder is equal to $0.0623\ inch^3$ .

6 0

3 years ago

The area of a rectangular park is 3/5 square mile. The length of the park is 7/8 mile. What is width of the park

Ira Lisetskai [31]

3/5 is 0.6
7/8 is 0.875
0.6/0.875 is 0.685714286
0.685714286 is 685714286/1000000000
(not so sure about it but that was what i came up with hope i helped)

6 0

3 years ago

What is the average rate of change of the function f(x) = 5x ^ 2 + 20x between x = 0 and x = 0.5

Vitek1552 [10]

9514 1404 393

Answer:

22.5

Step-by-step explanation:

The average rate of change on the interval [a, b] is the ratio ...

(f(b) -f(x))/(b -a)

For your function and interval, it is ...

(f(0.5) -f(0))/(0.5 -0)

Since f(0) = 0, this reduces to ...

average rate of change = 2·f(0.5) = 2(5(0.5)² +20(0.5)) = 2(5/4 +10)

average rate of change = 22.5

8 0

3 years ago

8-x+4-2-8x= What does x equal

goldfiish [28.3K]

Answer:

-9x + 10

Step-by-step explanation:

3 0

3 years ago

How do I simplify 1/-5z^-5?

belka [17]

$\bf \cfrac{1}{-5z^{-5}}\\\\
-------------------------\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\\ \quad \\
% negative exponential denominator
a^{{ n}} \implies \cfrac{1}{a^{- n}}
\qquad \qquad 
\cfrac{1}{a^{- n}}\implies \cfrac{1}{\frac{1}{a^{ n}}}\implies a^{{ n}} \\\\
-------------------------\\\\
thus
$

$\bf -\cfrac{1}{5}\cdot \cfrac{1}{z^{-5}}\implies -\cfrac{1}{5}\cdot \cfrac{1}{\frac{1}{z^5}}\implies -\cfrac{1}{5}\cdot \cfrac{\frac{1}{1}}{\frac{1}{z^5}}\implies -
\cfrac{1}{5}\cdot \cfrac{1}{1}\cdot \cfrac{z^5}{1}
\\\\\\
-\cfrac{z^5}{5}$

3 0

2 years ago