Answer:
1. (2,2)
2. (-20, -1)
3. (4,3)
Step-by-step explanation:
See attached images
Answer:
c) 0.932
99% confidence interval for average weights of all packages sold in small meat trays.
(0.932 ,1.071)
Step-by-step explanation:
Explanation:-
Given random sample of 35 packages in small meat trays produced weight with an average of 1.01 lbs. and standard deviation of 0.18 lbs.
size of the sample 'n' = 35
mean of the sample x⁻= 1.01lbs
standard deviation of the sample 'S' = 0.18lbs
<u>The 99% confidence intervals are given by</u>

The degrees of freedom γ=n-1 =35-1=34
tₐ = 2.0322
99% confidence interval for average weights of all packages sold in small meat trays

( 1.01 - 0.06183 , 1.01+0.06183)
(0.932 ,1.071)
<u>Final answer</u>:-
<u>99% confidence interval for average weights of all packages sold in small meat trays.</u>
<u>(0.932 ,1.071)</u>
The answer is 125
To solve:
(3+2)=5. *Parentheses first*
5^3 = 125
As the 2 quadrilaterals are congruent the sides of one quadrilateral are equal to the corresponding sides of the other quadrilateral
Hence,
AB = PQ
RQ = BC
AD = PS
DC = RS
Since terms for both AB and PQ are given we can equate the terms and find m
5m -9 = m + 11
5m -m = 11 + 9
4m = 20
m = 5
Correct answer is D , 5
Given:
The scale factor is 1:12.
Dimension of model = 32 cm
To find:
The actual dimension in m.
Solution:
Let x be the actual dimension.
The scale factor is 1:12 and the dimension of model is 32 cm.

On cross multiplication, we get


![[\because 1\ m=100\ cm]](https://tex.z-dn.net/?f=%5B%5Cbecause%201%5C%20m%3D100%5C%20cm%5D)
Therefore, the actual dimension is 3.84 m.