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Ray Of Light [21]
3 years ago
8

Sean has 1/5 of a cupcake and 1/5 of a large cake. Does the sum 1/5 + 1/5 make sense in this situation

Mathematics
2 answers:
svetlana [45]3 years ago
3 0

Answer:

The size of the cupcake and the size of the cake differ, so when your saying 1/5 of the cupcake, 1/5 of a cupcake is not the same as 1/5 of the cake . Idk if this will help, but I gave you a suggestion!

Step-by-step explanation:

dusya [7]3 years ago
3 0

Answer:

The sum of 1/5 and 1/5 does make sense if you add you will get 1.

Step-by-step explanation:

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Can anyone help me solve these linear systems using substitution?
Andre45 [30]

Answer:

1. (2,2)

2. (-20, -1)

3. (4,3)

Step-by-step explanation:

See attached images

4 0
1 year ago
Read 2 more answers
The meat department of a local supermarket packages ground beef using meat trays of two sizes: 1 designed to hold 1 lb of meet a
r-ruslan [8.4K]

Answer:

c) 0.932

99% confidence interval for average weights of all packages sold in small meat trays.

(0.932 ,1.071)

Step-by-step explanation:

Explanation:-

Given random sample of 35 packages in small meat trays produced weight with an average of 1.01 lbs. and standard deviation  of 0.18 lbs.

size of the sample 'n' = 35

mean of the sample x⁻= 1.01lbs

standard deviation of the sample 'S' = 0.18lbs

<u>The 99% confidence intervals are given by</u>

(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } , x^{-} +t_{\alpha } \frac{S}{\sqrt{n} } )

The degrees of freedom γ=n-1 =35-1=34

tₐ =  2.0322

99% confidence interval for average weights of all packages sold in small meat trays

(1.01 - 2.0322 \frac{0.18}{\sqrt{35} } , 1.01+2.0322 \frac{0.18}{\sqrt{35} } )

( 1.01 - 0.06183 , 1.01+0.06183)

(0.932 ,1.071)

<u>Final answer</u>:-

<u>99% confidence interval for average weights of all packages sold in small meat trays.</u>

<u>(0.932 ,1.071)</u>

5 0
3 years ago
Find a value for the following: (3+2)^3
dsp73
The answer is 125


To solve:

(3+2)=5. *Parentheses first*

5^3 = 125
8 0
3 years ago
Read 2 more answers
Given that ABCD congruent to PQRS, solve for m<br><br><br> A.0.5<br> B.2.5<br> C.3<br> D.5
34kurt
As the 2 quadrilaterals are congruent the sides of one quadrilateral are equal to the corresponding sides of the other quadrilateral
Hence,
AB = PQ
RQ = BC
AD = PS
DC = RS
Since terms for both AB and PQ are given we can equate the terms and find m
5m -9 = m + 11
5m -m = 11 + 9
4m = 20
m = 5
Correct answer is D , 5
3 0
3 years ago
Find the missing dimension use the scale factor 1:12 model 32 cm find the actual in m
gizmo_the_mogwai [7]

Given:

The scale factor is 1:12.

Dimension of model = 32 cm

To find:

The actual dimension in m.

Solution:

Let x be the actual dimension.

The scale factor is 1:12 and the dimension of model is 32 cm.

\dfrac{1}{12}=\dfrac{32}{x}

On cross multiplication, we get

x=32\times 12

x=384\ cm

x=3.84\ m             [\because 1\ m=100\ cm]

Therefore, the actual dimension is 3.84 m.

6 0
2 years ago
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