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3 years ago

Find the length of a segment with endpoints Y(2, 8) and Z(- 2, 5) .

Mathematics

1 answer:

Andrej [43]3 years ago

3 0

<em>The distance the length of a segment with endpoints Y(2, 8) and Z(-2, 5) is 5 units</em>

<h2>Explanation:</h2>

Endpoints of a Line segments are places where they end or stop. Line segments are named after their endpoints. In this case, those endpoints are Y and Z, so the line segment would be:

$\overline{YZ} \ or \ \overline{ZY}$

To find the length of this segment with endpoints Y(2, 8) and Z(-2, 5), let's use the Distance Formula:

$d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

$Let's \ write: \\ \\ Y(x_{1},y_{1}) \rightarrow Y(2, 8) \\ \\ Z(x_{2},y_{2}) \rightarrow (-2, 5) \\ \\ \\ Substituting: \\ \\ d=\sqrt{(-2-2))^2+(5-8)}^2 \\ \\ d=\sqrt{(-4)^2+(-3)^2} \\ \\ d=\sqrt{16+9} \\ \\ d=\sqrt{25} \\ \\ \boxed{d=5}$

Finally, <em>the distance the length of a segment with endpoints Y(2, 8) and Z(-2, 5) is 5 units</em>

<h2>Learn more:</h2>

Distance Formula: brainly.com/question/10134840

#LearnWithBrainly

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Help it’s slope idk how to do it

Over [174]

a. $\boxed{y-602=\frac{2}{3}(x-3)}$

b. For every month the pine tree grows about 0.67 inches.

c. <em> </em>It represents the height of the tree at the moment Ariel started to record the heights.

<h2>Explanation:</h2>

In this exercise we have that in July Ariel recorded the height of a pine tree and how quickly it was expected to grow in next several months. From the Table, we can get the following points:

$P_{1}(3,602) \\ \\ P_{2}(6,604) \\ \\ P_{3}(q,606) \\ \\ P_{4}(12,608)$

It is obvious that this problem follows a linear equation, so our goal is to find the equation that matches the Table.

The point slope form of the equation of a line is:

$y-y_{1}=m(x-x_{1}) \\ \\ Where: \\ \\ m:Slope \\ \\ (x_{1}, y_{1}):A \ point \ on \ the \ line$

Finding (m):

$Using: \\ \\ P_{1}(x_{1},y_{1}) \rightarrow P_{1}(3,602) \\ \\ P_{2}(x_{2}, y_{2}) \rightarrow P_{2}(6,604) \\ \\ m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{604-602}{6-3} \\ \\ m=\frac{2}{3}$

Finally, the equation of the line is:

$(x_{1}, y_{1}) \rightarrow (3,602) \\ \\ \boxed{y-602=\frac{2}{3}(x-3)}$

In this case, we have that:

The x-axis represents the <em>Number of Months </em>the pine tree was expected to grow.
The y-axis represents the <em>Height of the Tree </em>in inches.

Since the slope o a line is:

$Slope=\frac{Change \ in \ y}{Change \ in \ x}=\frac{2}{3}$

Then, this means that<em> every three months the pine tree grows two inches, </em><em>or </em><em>for every month the pine tree grows about 0.67 inches.</em>

The y-intercept can be found setting $x=0$ . So, from our equation:

$y-602=\frac{2}{3}(x-3)} \\ \\ \\ If \ x=0: \\ \\ y-602=\frac{2}{3}(0-3) \\ \\ y-602=-2 \\ \\ Solving \ for \ y: \\ \\ y=602-2 \\ \\ y=600$

So the y-intercept is $y=600$ and<em> represents the height of the tree at the moment Ariel started to record the heights.</em>

<h2>Learn more:</h2>

Slope Intercept form: brainly.com/question/4192440

#LearnWithBrainly

4 0

3 years ago

6. A car dealership would like to estimate the mean mpg of its new model car with 90% confidence. The population is normally dis

Yakvenalex [24]

Answer:

92.9997< $\mu$ <99.5203

Step-by-step explanation:

Using the formula for calculating the confidence interval expressed as:

CI = xbar ± Z * S/√n where;

xbar is the sample mean

Z is the z-score at 90% confidence interval

S is the sample standard deviation

n is the sample size

Given parameters

xbar = 96.52

Z at 90% CI = 1.645

S = 10.70.

n = 25

Required

90% confidence interval for the population mean using the sample data.

Substituting the given parameters into the formula, we will have;

CI = 96.52 ± (1.645 * 10.70/√25)

CI = 96.52 ± (1.645 * 10.70/5)

CI = 96.52 ± (1.645 * 2.14)

CI = 96.52 ± (3.5203)

CI = (96.52-3.5203, 96.52+3.5203)

CI = (92.9997, 99.5203)

<em>Hence a 90% confidence interval for the population mean using this sample data is 92.9997<</em> $\mu$ <em><99.5203</em>

4 0

3 years ago

A rock is released from rest and freely falls 70 m to the ground. What is its velocity just before impact? A. 1.2 m/s B. 7.0 m/s

Yuri [45]

Answer:

37.04 m/s

Step-by-step explanation:

we can use the equation x = x0 + v0t + 1/2at^2

a = -9.8 m/s^2, the acceleration due to gravity

x0 = 70 m, the starting point of x

v0 = 0 m/s

x = 0

this will allow us to solve for time

0 = 70 + 0 +-4.9t^2

t = 3.779

now we can use the equation v = v0 + at

v = 0 + 9.8(3.77)

v = 37.04 m/s

5 0

3 years ago

Solve for x. 7 + 11x + 60 = -13 + 3x

Snowcat [4.5K]

Answer:

x = -10

Step-by-step explanation:

Step 1: Write equation

7 + 11x + 60 = -13 + 3x

Step 2: Solve for <em>x</em>

Combine like terms: 11x + 67 = -13 + 3x
Subtract 3x on both sides: 8x + 67 = -13
Subtract 67 on both sides: 8x = -80
Divide both sides by 8: x = -10

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

7 + 11(-10) + 60 = -13 + 3(-10)

67 - 110 = -13 - 30

-43 = -43

6 0

3 years ago

Given the weekly demand curve of a local wine producer is p= 50-0.1q, and that the total cost function is c= 1500+ 10q, where q

Mamont248 [21]

Answer:

Step-by-step explanation:

From the given information:

a) To express the weekly profit as a function of price

Cost =C(q) = 1500 + 10q

Revenue = p×q = (50 − 0.1q)×q = 50q - 0.1q²

Revenue = 50q - 0.1q²

Weekly profit = Revenue - Cost

P(q) = (50q -0.1q²) - (1500 + 10q)

P(q)= -0.1 q² + 40 q - 1500

However, q = 500 - 10 p using p = 50 − 0.1q

P= -0.1 (500 - 10 p)² + 40 (500 - 10 p) - 1500

P= -10 p² + 600 p - 6500

The price at which the bottle of the wine must be sold to realise a maximum profit can be determined by finding the derivative and then set it to 0

P' = 0

= -20p+600 = 0

20p = 600

p = 600/20

p = $30

The maximum profit that can be made by the producer is:

P= -10(30)² + 600(30) - 6500

P = - 9000 + 18000 - 6500

P = $2500

5 0

3 years ago