Answer:
-10y + 10.5
Step-by-step explanation:
5 - 2y + (-8y) + 5.5
5 - 2y - 8y +5.5
-10y + 10.5
Answer: A) .1587
Step-by-step explanation:
Given : The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.30 ounces and a standard deviation of 0.20 ounce.
i.e.
and 
Let x denotes the amount of soda in any can.
Every can that has more than 12.50 ounces of soda poured into it must go through a special cleaning process before it can be sold.
Then, the probability that a randomly selected can will need to go through the mentioned process = probability that a randomly selected can has more than 12.50 ounces of soda poured into it =
![P(x>12.50)=1-P(x\leq12.50)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{12.50-12.30}{0.20})\\\\=1-P(z\leq1)\ \ [\because z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.8413\ \ \ [\text{By z-table}]\\\\=0.1587](https://tex.z-dn.net/?f=P%28x%3E12.50%29%3D1-P%28x%5Cleq12.50%29%5C%5C%5C%5C%3D1-P%28%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5Cleq%5Cdfrac%7B12.50-12.30%7D%7B0.20%7D%29%5C%5C%5C%5C%3D1-P%28z%5Cleq1%29%5C%20%5C%20%5B%5Cbecause%20z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3D1-0.8413%5C%20%5C%20%5C%20%5B%5Ctext%7BBy%20z-table%7D%5D%5C%5C%5C%5C%3D0.1587)
Hence, the required probability= A) 0.1587
- Your answer is no solution.
- Because if we transpose 10x to the left hand side with a change in the symbol, then it will become 0.
- 10x - 1 = 10x +4
- or, 10x - 10x = 4 + 5
- or, 0 = 9
- Hence, the equation has <em><u>no solution</u></em>.
Hope you could get an idea from here.
Doubt clarification - use comment section.
Answer:
The x - axis
Step-by-step explanation:
The line that is horrizontal is always the x - axis
Amount earned by Sharon per item sold = $25
Base salary of Sharon per week = $100
Amount that needs to be earned by Sharon per week = $700
Let us assume the number of items sold by Sharon per week = x
Then
100 + 25x = 700
25x = 700 - 100
25x = 600
x = 600/25
= 24
So Sharon needs to sell 24 items to earn a total of $700 per week. I hope you have understood the method of solving such problems.