The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
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ANSWER: symmetric property
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Add the who numbers: 4 + 2 = 6
You are correct, it's C. 6
The interest paid is Rs 10000
The rate of interest is 20%
Step-by-step explanation:
Step 1 :
Amount borrowed by Mr. Satyal = Rs 50000
Amount repaid = Rs 60000
Interest is charged on the principal amount and the amount repaid will be the sum of the interest paid plus the principal amount
Hence the interest paid is 60000 - 50000 = Rs 10000
Step 2:
The rate of interest is calculated as follows :
Divide the interest calculated by the principal amount and is expressed as percentage.
Hence the interest rate =
× 100 = 20%
Step 3 :
The interest paid is Rs 10000
The interest rate is 20%
Answer:
1r
Step-by-step explanation:
(5r-4)(2r-6r+4)
1(5r-4)+1(2r-6r+4)
5r-4+2r-6r+4
5r+2r-6=1r
1r-4+4
-4+4=0
1r