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2 years ago

PLEASE HELP ME !!!

Mathematics

2 answers:

natulia [17]2 years ago

5 0

Answer:

(B) (7x-6)(7x+6)

Amiraneli [1.4K]2 years ago

3 0

Answer:

(B) (7x - 6 ) ( 7x + 6)

Step-by-step explanation:

49x^2 - 36

This is the difference of squares

(7x)^2 - 6^2

We can factor this as

(a^2 -b^2) =(a-b) (a+b)

(7x)^2 - 6^2 = (7x-6) (7x+6)

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How do you multiply 77.22 x .8 ? With the work shown

Tpy6a [65]

first line up the decimals

77.22

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2 years ago

Read 2 more answers

Please Help! Subtract. (2x^4−x^2+5x−2)−(−x^4+3x^3+2x^2−1)

kifflom [539]

Answer:

Heya!!

here's your answer

3x^4 − 3x^3 − 3x^2 + 5x −1

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2 years ago

Periodically, Merrill Lynch customers are asked to evaluate Merrill Lynch financial consultants and services. Higher ratings on

Anuta_ua [19.1K]

Answer:

a) Null hypothesis: $\mu_{A} \leq \mu_{B}$

Alternative hypothesis: $\mu_{A} > \mu_{B}$

b) $t=\frac{6.82-6.25}{\sqrt{\frac{0.64^2}{16}+\frac{0.75^2}{10}}}}=1.992$

c) $p_v =P(t_{(24)}>1.992)=0.0289$

d) If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the more experience consultant A have a significant higher rate compared to the consultant B with less experience at 5% of significance.

Step-by-step explanation:

1) Data given and notation

$\bar X_{A}=6.82$ represent the mean for the sample of Consultant A

$\bar X_{B}=6.25$ represent the mean for the sample of Consultant B

$s_{A}=0.64$ represent the sample standard deviation for the sample of Consultant A

$s_{B}=0.75$ represent the sample standard deviation for the sample of bonsultant B

$n_{A}=16$ sample size selected for the Consultant A

$n_{B}=10$ sample size selected for the Consultant B

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

Part a: State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean for the Consultant A (more experience) is higher than the mean for the Consultant B, the system of hypothesis would be:

Null hypothesis: $\mu_{A} \leq \mu_{B}$

Alternative hypothesis: $\mu_{A} > \mu_{B}$

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{A}-\bar X_{B}}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Part b: Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{6.82-6.25}{\sqrt{\frac{0.64^2}{16}+\frac{0.75^2}{10}}}}=1.992$

Part c: P-value

The first step is calculate the degrees of freedom, on this case:

$df=n_{A}+n_{B}-2=16+10-2=24$

Since is a one side test the p value would be:

$p_v =P(t_{(24)}>1.992)=0.0289$

Part d: Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the more experience consultant A have a significant higher rate compared to the consultant B with less experience at 5% of significance.

5 0

2 years ago

Jeremy uses 6 pieces of rectangular

gogolik [260]

Answer:1000cm

Step-by-step explanation:

Volume=length ×width×height

Each side is 10

10×10×10=1000

5 0

3 years ago

What is 3.1666666667 as a fraction

never [62]

3 1666666667⁄10000000000

7 0

2 years ago