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mart [117]
3 years ago
14

Which is the base shape of this priam​

Mathematics
1 answer:
tatiyna3 years ago
4 0

Answer:

rectagle

Step-by-step explanation:

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Approximate √39 to the nearest whole number
vladimir2022 [97]
36 < 39 < 49

√36 < √39 < √49

6 < √39 < 7

√39 ≈ 6
4 0
3 years ago
What is the volume of this prism
Rainbow [258]

Answer:

36 cubic units

Step-by-step explanation:

length x width x height

you don’t need to pay attention to 6.97 because that’s not the real height. The real height is 4 (the straight line)

3x3x4 = 36 cubic units

4 0
3 years ago
Read 2 more answers
Below are tabulated a number of Rockwell G hardness values that were measured on a single steel specimen. Compute
Mashcka [7]

Answer:

a) 48.408

b) 1.235

Step-by-step explanation:

a)

The average hardness value xbar can be computed as

xbar=sum of values/number of values

xbar=(46.5+46.9+49.4+50.3+49.8+48.8+47+47.7+48.3+49.4+47.8+49)/12

xbar=580.9/12

xbar=48.408 (rounded to 3 decimal places).

The average hardness value is 48.408.

b)

The standard deviation hardness value s can be computed as

s=\sqrt{\frac{sum(x-xbar)^2}{n-1} }

x              x-xbar  (x-xbar) ²

46.5  -1.90833 3.64174

46.9  -1.50833 2.27507

49.4    0.99167 0.98340

50.3     1.89167 3.57840

49.8     1.39167 1.93674

48.8    0.39167 0.15340

47.0           -1.40833 1.98340

47.7   -0.70833 0.50174

48.3           -0.10833 0.01174

49.4    0.99167  0.98340

47.8           -0.60833 0.37007

49.0    0.59167 0.35007

Total                               16.7692

s=\sqrt{\frac{16.7692}{12-1} }

s=\sqrt{\frac{16.7692}{11} }

s=\sqrt{1.5245}

s=1.2347

s=1.235 (rounded to 3 decimal places)

The standard deviation hardness value is 1.235.

4 0
3 years ago
G=4ca-3ba, find a <br>Also plz show how u found the answer.
lina2011 [118]
G=4ca-3ba <=> G=a(4c-3b)

                   <=> a=G/(4c-3b)
8 0
3 years ago
Read 2 more answers
Val needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 42-m-42-m squar
oee [108]

The area enclosed by the figure is 4533.48 square meters.

<u>Step-by-step explanation:</u>

Side length of the square = 42m

The semicircle is attached to each side of the square. So the diameter of the semicircle is the length of the square.

Radius of the semicircle = 21m

Area of the square = 42 x 42 = 1764 square meters

Area of 1 semicircle = π(21 x 21) /2

= (3.14) (441) /2

= 1384.74/2

= 692.37 square meters

Area of 4 semicircle = 4 x 692.37

= 2769.48 square meters

Total area = 1764 + 2769.48

= 4533.48 square meters

The area enclosed by the figure is 4533.48 square meters.

7 0
3 years ago
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