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3 years ago

Choose the equation that shows a step in the process of completing the square on the given quadratic. y = x2 + 8x – 3

Mathematics

2 answers:

kolezko [41]3 years ago

4 0

Answer:

Step-by-step explanation:

y=x²+8x-3

=x²+8x+(4)²-(4)²-3

=(x+4)²-16-3

or y=(x+4)²-19

Leya [2.2K]3 years ago

4 0

Answer:

the answer is y=x^2+8x+16-3-16 or C.

Step-by-step explanation:

The next answer is 4 and -19

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Answer:

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3 years ago

Which of the following is a point on the graph of y-7=3(x-5)

kogti [31]

Answer: (5, 7)

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y2 - y1 = m (x2 - x1)

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4 years ago

Total solar eclipses occur on a regular and predictable basis. One that could be viewed in parts of the United States occurred o

Ivenika [448]

Answer:

Step-by-step explanation:

The previous solar eclipse occured on March 7 , 1970 .

saros cycle has duration of 18 years , 11 + 1/3 days

So the earth goes 1 / 3 of its daily rotation beyond its previous location in the next solar eclipse on the earth . In order that we get solar eclipse on the same point on the earth , we shall have to wait for third solar eclipse

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3 years ago

A ball is thrown into the air and its position is given by h ( t ) = − 6.3 t 2 + 53 t + 24 where h is the height of the ball in

nordsb [41]

Answer:

$h'(t) = -12.6 t +53$

Now we can set up the derivate equal to 0 and we have:

$-12.6 t +53 = 0$

And solving for t we got:

$t = \frac{53}{12.6}= 4.206$

For the second derivate respect the time we got:

$h''(t) = -12.6$

So then we can conclude that t = 4.206 is a maximum for the function.

And the corresponding height would be:

$h(t=4.206) = -6.3(4.206)^2 +53*4.206+24= 135.468 ft$

So the maximum occurs at t = 4.206 s and with a height of 135.468 m

Step-by-step explanation:

For this case we have the following function:

$h(t) = -6.3t^2 +53 t+24$

In order to maximize this function we need to take the first derivate respect the time and we have:

$h'(t) = -12.6 t +53$

Now we can set up the derivate equal to 0 and we have:

$-12.6 t +53 = 0$

And solving for t we got:

$t = \frac{53}{12.6}= 4.206$

For the second derivate respect the time we got:

$h''(t) = -12.6$

So then we can conclude that t = 4.206 is a maximum for the function.

And the corresponding height would be:

$h(t=4.206) = -6.3(4.206)^2 +53*4.206+24= 135.468 ft$

So the maximum occurs at t = 4.206 s and with a height of 135.468 m

8 0

4 years ago