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MrRissso [65]
4 years ago
12

Jim says that the marked yellow paths show the shortest path to the tent. Is he correct ? Explain

Mathematics
1 answer:
aev [14]4 years ago
6 0
Is there a picture so I can help
You might be interested in
The value of 4a( a - 3 ) is :
liubo4ka [24]

Answer:

Its -12 if a is meant to be multiplied

3 0
3 years ago
Simplify (-3c^-3w^5)^3<br> A -9w^8<br> B. -27cw^8<br> C. w^15/27c^9<br> D.-27w^15/c^9
kenny6666 [7]

Answer:

\large\boxed{D.\ \dfrac{-27w^{15}}{c^9}}

Step-by-step explanation:

(-3c^{-3}w^5)^3\qquad\text{use}\ (ab)^n=a^nb^n\\\\=(-3)^3(c^{-3})^3(w^5)^3\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=-27c^{-3\cdot3}w^{5\cdot3}=-27c^{-9}w^{15}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\=-27\left(\dfrac{1}{c^9}\right)w^{15}=\dfrac{-27w^{15}}{c^9}

4 0
3 years ago
At the same time, two trains start toward each other on parallel tracks, 450 miles apart. Train A’s constant rate is 55 mph. Tra
r-ruslan [8.4K]

55 + 65 = 120

450/120 = 3.75 hrs

= 3h 45m


3 0
4 years ago
I need help with this as well
cupoosta [38]
<span>n 19 -----------> AB/AC=(4/6)=2/3<span>

n 20 ------------> BC/CD=[AC-AB]/[AD-AC]=(6-4)/(9-6)=2/3

n 21-------------> BD/AE=[AD-AB]/[AE]=(9-4)/(12)=5/12

n 22   7 and 28  find the geometric mean of the two number
step 1
Multiply the two numbers together: 
28*7=196 
step 2
take the square root: 
<span><span>sqrt(196)=14 
</span>the answer is 14</span>

n 23  Simplify the ratio 10 ft/30 in---> divided between 2 both members
5 ft/15 in-----> divided between 5 both members ---> 1 ft/3 in</span><span>

n 24 
<span>if AB=4 -------></span></span> AB~FG
</span><span>FG=8<span>
then
</span></span>AB*factor=FG-------- > 4*factor=8-- > factor=8/4=2
the figure ABCDE is half of the figure FGHJK
then<span>
BC=4
AE=CD=5
and 
ED=6
therefore
<span>the perimeter=[4+4+5+5+6]=24 units</span></span>
4 0
3 years ago
What is 4 square root 7^3 in exponential form?
Gnesinka [82]

Answer:

Given the radical form: 4\sqrt{7^3}

Use the exponent rules:

\sqrt[n]{a^m} = (a^m)^{\frac{1}{n}} = a^{\frac{m}{n}}

we can write \sqrt{7^3} as:

\sqrt{7^3} = (7^3)^{\frac{1}{2}} = 7^{\frac{3}{2}}

then;

4\sqrt{7^3} = 4 \cdot 7^{\frac{3}{2}}

Therefore, 4\sqrt{7^3} in exponential form is 4 \cdot 7^{\frac{3}{2}}


8 0
3 years ago
Read 2 more answers
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