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Digiron [165]
3 years ago
12

Ms. Omar runs the School tennis club. She has a bin of tennis balls and rackets. For every 5 tennis balls in the bin, there are

3 tennis rackets. Draw a model to show the ratio of the tennis balls to tennis rackets.

Mathematics
1 answer:
atroni [7]3 years ago
7 0

Answer:

Step-by-step explanation:

5:3. there are 5 balls, and 3 rackets

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Miguel napped for 2 2/5 hours. Danalya napped too. Combined they napped for 3 3/4 hours
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Answer:

Danalya napped 1 7/20 hours.

Step-by-step explanation:

Rewriting our equation with parts separated

=3+3/4−2−2/5

Solving the whole number parts

3−2=1

Solving the fraction parts

3/4−2/5=?

Find the LCD of 3/4 and 2/5 and rewrite to solve with the equivalent fractions.

LCD = 20

15/20−8/20= 7/20

Combining the whole and fraction parts

1+7/20= 1 7/20

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3 years ago
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Simplify: 6x^-2<br><br> a) 1/6x^2<br> b) 6/x^2<br> c) x^2/6<br> d) 1/36x^2
Salsk061 [2.6K]

Answer:

The correct answer choice is <u>option B. 6/x^2</u>

Step-by-step explanation:

8 0
3 years ago
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A company that manufactures guitars has a fixed cost of $100,000. It costs $100 to produce each guitar and the selling price is
miv72 [106K]

a. Write the cost function:: C(x) = 100x + 100,000 where x is number of guitars

---------------------------------

b. Write the revenue function:: R(x) = 300x where x is number of guitars

-----------------------

c. Find the profit function.

Profit = Revenue - Cost

P(x) = R(x) - C(x)

P(x) = [ R(x) ] - [ C(x) ]

P(x) = [ 300x ] - [ 100x+100,000 ]

P(x) = 300x - 100x-100,000

P(x) = 200x - 100,000

The break even point is when the profit is 0 dollars. You don't lose any money. And you don't gain any money.

Solve 125x - 100,000 = 0

125x = 100,000

x = 800 (# of guitars made and sold)

7 0
3 years ago
I REALLY NEED HELP ON THIS PLS HELP
Eva8 [605]

Part (a)

Answer: See the attached image below to see the filled out chart.

Note how rational and irrational numbers have nothing in common. This means there is no overlap. So they go in the rectangles. The two sets of numbers join up to form the entire set of real numbers.

Integers are in the set of rational numbers. This is because something like 7 is also 7/1; however 1/7 is not an integer. So not all rational numbers are integers. The larger purple circle is the set of integers.

The smaller blue circle is the set of whole numbers. The set of whole numbers is a subset of integers. Recall the set of whole numbers is {0,1,2,3,...} so we ignore the negative values only focusing on 0 and positive numbers that don't have any fractional values. In contrast, the set of integers is {..., -3, -2, -1, 0, 1, 2, 3, ...} here we do include the negatives.

============================================================

Part (b)

1) Some irrational numbers are integers.

This is false. An irrational number is not rational. The set of integers is contained entirely in the set of rational numbers.

---------------------------------

2) Some whole numbers are not irrational numbers.

This is false. The statement implies that some whole numbers are irrational, but the set of whole numbers is inside the set of rational numbers, which has no overlap with the irrationals. The statement should be "All whole numbers are not irrational numbers".

---------------------------------

3) All rational numbers are whole numbers.

This is false. A rational number like 1/3 is not a whole number.

---------------------------------

4) All integers are whole numbers

This is false. An integer like -44 is not a whole number because the set of whole numbers is {0,1,2,3,...} and we're not including negative values.

---------------------------------

In summary, all four statements for part (b) are false.

8 0
3 years ago
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