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son4ous [18]
3 years ago
15

What is the radius of a sphere with a volume of 12,348 π cubic feet?

Mathematics
1 answer:
vova2212 [387]3 years ago
5 0

Answer:

Radius = 21

Step-by-step explanation:

Volume of a sphere = 4/3 * pie * radius^3

12,348 pie = 4/3 * pie * radius ^3

12,348 = 4/3 * radius^3

(12,348 * 3)/ 4 = radius^3

9261 = radius^3

radius = \sqrt[3]{9261}

radius = 21

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A triangular lot has sides of 215m, 185m, and 125m. Find the measures of the angles at its corners
Vlada [557]

Answer:

The measures of the angles at its corners are 59.1\°,35.4\°,85.5\°

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle A

Applying the law of cosines

185^{2}= 215^{2}+125^{2}-2(215)(125)cos(A)

2(215)(125)cos(A)= 215^{2}+125^{2}-185^{2}

cos(A)= [215^{2}+125^{2}-185^{2}]/(2(215)(125))cos(A)=0.513953

A=arccos(0.513953)=59.1\°

step 2

Find the measure of angle B

Applying the law of cosines

125^{2}= 215^{2}+185^{2}-2(215)(185)cos(B)

2(215)(185)cos(B)= 215^{2}+185^{2}-125^{2}

cos(B)= [215^{2}+185^{2}-125^{2}]/(2(215)(185))cos(B)=0.81489

B=arccos(0.81489)=35.4\°

step 3

Find the measure of angle C

Applying the law of cosines

215^{2}= 125^{2}+185^{2}-2(125)(185)cos(C)

2(125)(185)cos(C)= 125^{2}+185^{2}-215^{2}

cos(C)= [125^{2}+185^{2}-215^{2}]/(2(125)(185))cos(C)=0.0784

C=arccos(0.0784)=85.5\°

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3 years ago
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Step-by-step explanation:

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2 years ago
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Strength [is proportional to] d^2
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strength2 = 800 kg * 3^2/2^2
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Answer:

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