-5x + 7 + 2x - 3 Simplify
2 answers:
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<u>EXPLANATION</u><u>:</u>
Given that
sin θ = 1/2
We know that
sin 3θ = 3 sin θ - 4 sin³ θ
⇛sin 3θ = 3(1/2)-4(1/2)³
⇛sin 3θ = (3/2)-4(1/8)
⇛sin 3θ = (3/2)-(4/8)
⇛sin 3θ = (3/2)-(1/2)
⇛sin 3θ = (3-1)/2
⇛sin 3θ = 2/2
⇛sin 3θ = 1
and
cos 2θ = cos² θ - sin² θ
⇛cos 2θ = 1 - sin² θ - sin² θ
⇛cos 2θ = 1 - 2 sin² θ
Now,
cos 2θ = 1-2(1/2)²
⇛cos 2θ = 1-2(1/4)
⇛cos 2θ = 1-(2/4)
⇛cos 2θ = 1-(1/2)
⇛cos 2θ = (2-1)/2
⇛cos 2θ = 1/2
Now,
The value of sin 3θ /(1+cos 2θ
⇛1/{1+(1/2)}
⇛1/{(2+1)/2}
⇛1/(3/2)
⇛1×(2/3)
⇛(1×2)/3
⇛2/3
<u>Answer</u> : Hence, the req value of sin 3θ /(1+cos 2θ) is 2/3.
<u>also</u><u> read</u><u> similar</u><u> questions</u><u>:</u> If sin Θ = 2/3 and tan Θ < 0, what is the value of cos Θ?
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The first step for solving this expression is to reduce the fraction with 11.
Now reduce the fraction with
.
Reduce the fraction one more time with
.
To take the root of a fraction,, we must take the root of the numerator and denominator separately. This rule will change the expression to the following:
Since we cannot simplify this fraction any further,, the final answer is going to be.
Let me know if you have any further questions.
:)
Now reduce the fraction with
Reduce the fraction one more time with
To take the root of a fraction,, we must take the root of the numerator and denominator separately. This rule will change the expression to the following:
Since we cannot simplify this fraction any further,, the final answer is going to be
Let me know if you have any further questions.
:)