Find the distance between the two points in simplest radical form. (8, -3)(6, -8)

Mathematics

2 answers:

Flura [38]3 years ago

8 0

Answer:

sqrt(29)

Step-by-step explanation:

distance = sqrt√( (x2 - x1)^ + (y2 - y1)^2 )

x1 = 6

x2 = 8

y1 = -8

y2 = -3

distance = sqrt( ( 8 - 6)^2 + (-3 - -8)^2 )

distance = sqrt( 2^2 + 5^2)

distance = sqrt(29)

fomenos3 years ago

5 0

Answer:

Step-by-step explanation:

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How do i solve functions?

Maksim231197 [3]

Most quadratic functions(which is what you have there, to a degree of 2) are solved using factoring and the zero product law. If you can not factor then you have to use the quadratic formula or graph it. However this one can be factored.
It's pretty simple to just factor it by inspection but I use the chart method, if you know decomposition that works as well.
Factoring gives us,
$(2x + 1)(x - 3) = 0$
Then you set each factor to 0 and solve for x,
$2x + 1 = 0$
$2x = - 1$
$x = \frac{ - 1}{2}$
And the second one,
$x - 3 = 0$
$x = 3$
The solutions to this equation are
x = -1/2, 3

6 0

3 years ago

After school Philippe spent 1 3/4 hours at baseball practice, 2 1/4 hours on homework, and 1/4 hour getting ready for bed. About

marshall27 [118]

Answer:

4 hours. 1 3/4 is about 2, and 2 1/4 rounds to 2. 1/4 would round to 0, but it would not affect the estimate's accuracy much because we rounded up by 1/4 on 1 3/4 already. Philipe spent about 4 hours on activities.

Step-by-step explanation:

4 0

2 years ago

If (-1, y) lies on the graph of y=2^2x then y=

zubka84 [21]

Answer:

y is 1/4 when x is -1 if I did interpret your equation right. Please see that I did.

I believe the equation to be $y=2^{2x}$ . If you meant $y=2^2x$ , please let me know.