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Alexus [3.1K]
3 years ago
14

Really need help with this problem

Mathematics
1 answer:
Brrunno [24]3 years ago
8 0

The equation of a circle is the equation that represents the circle on the coordinate plane

The equation of the circle is (x +3)^2 + (y -6)^2  = 13'

From the attached figure, we have the following parameters:

  • Center: (a,b) = (-3, 6)
  • Point on the circumference: (x,y) = (0,8)

Start by calculating the radius r using the following distance formula

d = \sqrt{(x -a)^2 +(y - b)^2}

So, we have:

r = \sqrt{(0 --3)^2 +(8 - 6)^2}

r = \sqrt{9 +4}

r = \sqrt{13}

Square both sides

r^2 = 13

The equation of the circle is then calculated as:

(x - a)^2 + (y -b)^2  = r^2

Substitute values for a and b

(x - -3)^2 + (y -6)^2  = r^2

This gives

(x +3)^2 + (y -6)^2  = r^2

Substitute r^2 = 13

(x +3)^2 + (y -6)^2  = 13

Hence, the equation of the circle is (x +3)^2 + (y -6)^2  = 13'

Read more about circle equations at:

brainly.com/question/1559324

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