Question

Really need help with this problem

Answer 1

The equation of a circle is the equation that represents the circle on the coordinate plane

The equation of the circle is $(x +3)^2 + (y -6)^2 = 13$'

From the attached figure, we have the following parameters:

• Center: (a,b) = (-3, 6)
• Point on the circumference: (x,y) = (0,8)

Start by calculating the radius r using the following distance formula

$d = \sqrt{(x -a)^2 +(y - b)^2}$

So, we have:

$r = \sqrt{(0 --3)^2 +(8 - 6)^2}$

$r = \sqrt{9 +4}$

$r = \sqrt{13}$

Square both sides

$r^2 = 13$

The equation of the circle is then calculated as:

$(x - a)^2 + (y -b)^2 = r^2$

Substitute values for a and b

$(x - -3)^2 + (y -6)^2 = r^2$

This gives

$(x +3)^2 + (y -6)^2 = r^2$

Substitute $r^2 = 13$

$(x +3)^2 + (y -6)^2 = 13$

Hence, the equation of the circle is $(x +3)^2 + (y -6)^2 = 13$'

Read more about circle equations at:

brainly.com/question/1559324