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Brrunno [24]
3 years ago
10

This equation shows how the cost of a charity gala depends on the number of attendees. d = 5.1a + 11.6 The variable a represents

the number of attendees, and the variable d represents the cost in dollars. How many attendees can there be, at most, if the budget for the charity gala is $98.30?
Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
5 0

$98.30=5.1a+11.6
98.30-11.6=5a+11.6-11.6
86.7=5a
86.7/5=5a/5
17.34=a
So only 17 people can attend

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alicia bought 205 pink and purple beads. she lost 3/5 of the pink beads and was given another 15 purple beads.
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Answer: sorry

Step-by-step explanation:

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3 years ago
Jane must get at least three of the four problems on the exam correct to get an A. She has been able to do 80% of the problems o
NISA [10]

Answer:

a) There is n 81.92% probability that she gets an A.

b) If she gets the first problem correct, there is an 89.6% probability that she gets an A.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the answer is correct, or it is not. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

For this problem, we have that:

The probability she gets any problem correct is 0.8, so \pi = 0.8.

(a) What is the probability she gets an A?

There are four problems, so n = 4

Jane must get at least three of the four problems on the exam correct to get an A.

So, we need to find P(X \geq 3)

P(X \geq 3) = P(X = 3) + P(X = 4)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 3) = C_{4,3}.(0.80)^{3}.(0.2)^{1} = 0.4096

P(X = 4) = C_{4,4}.(0.80)^{4}.(0.2)^{0} = 0.4096

P(X \geq 3) = P(X = 3) + P(X = 4) = 2*0.4096 = 0.8192

There is n 81.92% probability that she gets an A.

(b) If she gets the first problem correct, what is the probability she gets an A?

Now, there are only 3 problems left, so n = 3

To get an A, she must get at least 2 of them right, since one(the first one) she has already got it correct.

So, we need to find P(X \geq 2)

P(X \geq 3) = P(X = 2) + P(X = 3)

P(X = 2) = C_{3,2}.(0.80)^{2}.(0.2)^{1} = 0.384

P(X = 4) = C_{3,3}.(0.80)^{3}.(0.2)^{0} = 0.512

P(X \geq 3) = P(X = 2) + P(X = 3) = 0.384 + 0.512 = 0.896

If she gets the first problem correct, there is an 89.6% probability that she gets an A.

3 0
3 years ago
The length of a rectangle is four more than three times the width. If the perimeter of this rectangle is at least 70 square cent
FrozenT [24]

Answer:

Step-by-step explanation:

Let L represent the length of the triangle.

Let W represent the width of the triangle.

The length of a rectangle is four more than three times the width. This means that

L = 3W + 4

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(L + W)

If the perimeter of this rectangle is at least 70 square centimeters, an inequality that can be solved to find the width of the rectangle is

2(L + W) ≥ 70

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7 0
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masha68 [24]
10 separated into 5 groups is 10/5
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5 0
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Read 2 more answers
A plant can manufacture 50 golf clubs per
Mazyrski [523]

Answer:

The correct equation is "y=30x+6147". A further explanation is given below.

Step-by-step explanation:

The given values are:

(x1, y1) = (50, 7647)

(x2, y2) = (100, 9147)

As we know,

The slope is,

⇒ m=\frac{y2-y1}{x2-x1}

On substituting the given values, we get

⇒     =\frac{9147-7642}{100-50}

⇒     =\frac{1500}{50}

⇒     =30

Now,

⇒ (y-y1)=m(x-x1)

On substituting the given values in the above equation, we get

⇒ y-7647=30(x-50)

⇒ y-7647=30x-1500

On adding "7647" both sides, we get

⇒ y-7647+7647=30x-1500+7647

⇒                        y=30x+6147

3 0
2 years ago
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