F(x)=x^3-9x
and
g(x)=x^2-2x-3
so you just need to divide f(x) by g(x)
Therefore:
f(x)/g(x) = (x^3-9x) / (x^2-2x-3)
and of course you need to factor these two function to see if some factor would cancel another
x^3-9x = x(x^2-9)=x(x-3)(x+3)
and
x^2-2x-3 = (x-3)(x+1)
Answer:
It’s A
Step-by-step explanation:
Answer:
- B. BC = 18 so ∆ABC ~ ∆DEF by SAS
Step-by-step explanation:
So, ∆ABC ~ ∆DEF by SAS.
<h3>
<u>------------------------------------</u></h3>