By using trigonometric relations, we will find that:
sin(θ) = (√33)/7 = √(33/49)
<h3>How to find the value of the sine?</h3>
Remember that for a right triangle, we have the relations:
cos(a) = (adjacent cathetus)/(hypotenuse)
sin(a) = (opposite cathetus)/(hypotenuse).
Here we know that:
cos(θ) = 4/7
Then we can say that we have a triangle with an adjacent cathetus of 4 units and a hypotenuse of 7 units. Now we need to find the other cathetus.
opposite cathetus = √(7^2 - 4^2) = √33
Then we can write:
sin(θ) = (√33)/7 = √(33/49)
If you want to learn more about trigonometry.
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Answer: 4
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![\displaystyle = \frac{x^2(y-2)}{3y} \\\\Put \ x = 3, \ y = -1\\\\= \frac{(3)^2(-1-2)}{3(-1)}\\\\= \frac{9(-3)}{-3} \\\\= 9 \\\\ \rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%3D%20%5Cfrac%7Bx%5E2%28y-2%29%7D%7B3y%7D%20%5C%5C%5C%5CPut%20%5C%20x%20%3D%203%2C%20%5C%20y%20%3D%20-1%5C%5C%5C%5C%3D%20%5Cfrac%7B%283%29%5E2%28-1-2%29%7D%7B3%28-1%29%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B9%28-3%29%7D%7B-3%7D%20%5C%5C%5C%5C%3D%209%20%5C%5C%5C%5C%20%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3><h3>Peace!</h3>
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Hope this helped!
<h2>~AnonymousHelper1807</h2>