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Verizon [17]
3 years ago
7

Given a polynomial p(x)=0, which two expressions could be a pair of irrational roots of the equation square root 2-3, 2-square r

oot 3, square root 3-2, 2+ square root 3, -square root 2+3 please help!
Mathematics
1 answer:
sasho [114]3 years ago
4 0

Answer:

  2-square root 3, 2+ square root 3

Step-by-step explanation:

If the polynomial has rational and real coefficients, the roots will be "conjugates" of each other. That is, the sum of the root should be a rational number. So, the irrational parts will be opposites, while the rational parts remain the same.

  2±√3 . . . can be the roots of p(x) when p(x) has rational real coefficients

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Setler [38]

Answer:

1. Y=-2x+3

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3 years ago
Really need help with this paper
Darina [25.2K]

Answer:

The answer to your question is below

Step-by-step explanation:

1.- (2b - 1) (b + 8) = 0

    2b - 1 = 0           b + 8 = 0

     b = 1/2              b = -8

2.- (x + 3)(x - 12) = 0

     x + 3 = 0            x - 12 = 0

     x = -3                  x = 12

3.- (4b+ 7)(b + 11)

    4b + 7 = 0           b + 11 = 0

      b = -7/4             b = -11

4.- (k - 8)(k + 6)

     k - 8 = 0             k + 6 = 0

    k = 8                   k = -6

5.- (2n + 12)(5n+ 10)

     2n + 12 = 0             5n + 10 = 0

       n = -12/2 = -6          n = -10/5 = -2

6.- (w - 3)(3w - 7)

      w - 3 = 0                3w - 7 = 0

      w = 3                        w = 7/3

7.- (6n - 5)(n - 10)

     6n - 5 = 0                n - 10 = 0

      n = 5/6                   n = 10

8.- (n + 12)((4n + 7)

     n + 12 = 0                 4n + 7 = 0

     n = -12                         n = -7/4

9.- (3b + 4)(5b - 10)

      3b + 4 = 0                 5b - 10 = 0

       b = -4/3                     b = 10/5 = 2

10.- (p - 6)(p + 10)

       p - 6 = 0                  p + 10 = 0

       p = 6                        p = -10

3 0
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Is these two correct?<br> Just to make sure.
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Answer:

It should be correct

Step-by-step explanation:

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