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Setler79 [48]
3 years ago
6

I need help as fast as possible

Mathematics
1 answer:
aivan3 [116]3 years ago
4 0

Answer:

36°

Step-by-step explanation:

Given,

Measurement of <3 = 2x+8

Measurement of <4 = 6x+12

Since both are supplementary,

Therefore,

<3 + <4. = 180° [linear pair]

=> 2x + 8 + 6x + 12 = 180

=> 2x + 6x + 8 + 12 = 180

=> 8x + 20 = 180

=> 8x = 180 - 20 = 160

=  > x =  \frac{160}{8}

=> x = 20

Now as we have got the value of x,

According to the question measurement of <4 is,

<4 = 6×4 + 12 = 24 + 12 = <u>36</u><u>°</u><u> (Ans)</u>

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Write an expression to represent: 3 minus the quotient of x and 4
alisha [4.7K]

The expression representing the sentence is $3 -\frac{x}{4}.

We have a sentence - "3 minus the quotient of x and 4".

We have to determine the expression that represents the sentence.

<h3>Express the statement - "The difference of x and y is equal to an irrational number" in the form of expression.</h3>

The expression representing the above statement is -

x - y = π.

According to the question, we have -

3 minus the quotient of x and 4.

Using the Division Algorithm -

x = 4q + r

Substituting r = 0 by introducing decimals in the quotient, we get -

q = $\frac{x}{4}

Therefore -

$3 -\frac{x}{4}

Hence, the expression representing the sentence is $3 -\frac{x}{4}.

To solve more questions on Expression modelling, visit the link below-

brainly.com/question/20876878

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En términos de π , ¿cuál es el volumen de la esfera?
vladimir1956 [14]

Answer:

Volumen de una fórmula de esfera. El volumen de una esfera es de 4/3 x x (diámetro / 2) 3, donde (diámetro / 2) es el radio de la esfera (d á 2 x r)

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4 years ago
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Given the rule, find the 8th term in the arithmetic<br> sequence.<br> an =3n + 4
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You simply substitute 8 for n

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3 years ago
Determine whether the series is convergent or divergent. 1 2 3 4 1 8 3 16 1 32 3 64 convergent divergent Correct:
Vanyuwa [196]

Answer:

This series diverges.

Step-by-step explanation:

In order for the series to converge, i.e. \lim_{n \to \infty} a_n =A it must hold that for any small \epsilon>0, there must exist n_0\in \mathbb{N} so that starting from that term of the series all of the following terms satisfy that  |a_n-A|n_0 .

It is obvious that this cannot hold in our case because we have three sub-series of this observed series. One of them is a constant series with a_n=1 , the other is constant with a_n=3 , and the third one has terms that are approaching infinity.

Really, we can write this series like this:

a_n=\begin{cases} 1 \ , \ n=4k+1, k\in \mathbb{N}_0\\ 2^{k}\ , \ n=2k, k\in \mathbb{N}_0\\3\ , \ n=4k+3, k\in \mathbb{N}_0\end{cases}

If we  denote the first series as b_n=1, we will have that \lim_{k \to \infty} b_k=1.

The second series is denoted as c_k=2^k and we have that \lim_{k \to \infty} c_k=+\infty.

The third sub-series d_k=3 is a constant series and it holds that \lim_{k \to \infty} d_k=3.

Since those limits of sub-series are different, we can never find such n_0\\ so that every next term of the entire series is close to one number.

To make an example, if we observe the first sub-series if follows that A must be equal to 1. But if we chose \epsilon =1, all those terms associated with the third sub-series will be out of this interval (A-1, A+1)=(0, 2).

Therefore, the observed series diverges.

5 0
4 years ago
How to add 2 5/8 plus 3/8
san4es73 [151]
I hope this is a joke but the answer is 3 because 5/8 and 3/8 make 8/8 which equals 1 and 1 plus 2 equals 3
6 0
4 years ago
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