She'll have 17 with a remainder, just divide 139 by 8.
To solve
if you have |a|=b, solve a=b and a=-b
|4x+12|=16
solve
4x+12=16 and 4x+12=-16
minus 12 both sides
4x=4 and 4x=-28
divide both sides by 4
x=1 and x=-7
Answer:
Janis, Carl, Catherine
Step-by-step explanation:
janis=1.666
carl=1.7
catherine=2.333
- The area of the circle is:
A=πr²
A is the area of the circle.
π=3.14
r is the radius of the circle.
- To calculate the area of <span> the sector indicated in the problem, you must apply the following formula:
As=(</span>θ/2π)πr²
As is the area of the sector.
θ is the central angle (θ=2π/9)
π=3.14
r is the radius.
- First, you must find the radius:
r=Diameter/2
r=20.6 mm/2
r=10.3 mm
- Now, you can substitute the values into the formula As=(θ/2π)πr². Then, you have:
As=(θ/2π)πr²
As=(2π/9/2π)(π)(10.3)²
As=(π/9π)(π)(10.3)²
As=(3.14/9x3.14)(3.14)(10.3)²
- Finally, the area of the sector is:
As= 37.01 mm²
Answer:
In the explanation
Step-by-step explanation:
Going to start with the sum identities
sin(x+y)=sin(x)cos(y)+sin(y)cos(x)
cos(x+y)=cos(x)cos(y)-sin(x)sin(y)
sin(x)cos(x+y)=sin(x)cos(x)cos(y)-sin(x)sin(x)sin(y)
cos(x)sin(x+y)=cos(x)sin(x)cos(y)+cos(x)sin(y)cos(x)
Now we are going to take the line there and subtract the line before it from it.
I do also notice that column 1 have cos(y)cos(x)sin(x) in common while column 2 has sin(y) in common.
cos(x)sin(x+y)-sin(x)cos(x+y)
=0+sin(y)[cos^2(x)+sin^2(x)]
=sin(y)(1)
=sin(y)