After using the slope formula your answer would be 5/0.1 but when simplifying your answer is 50
The circumference of this circle is c=94.25ft
Answer:
40.5°
Step-by-step explanation:
The relevant trig relation is ...
Tan = Opposite/Adjacent
In this triangle, that means ...
tan(x°) = 4.7/5.5
The angle is found using the inverse function:
x° = arctan(4.7/5.5) ≈ 40.5°
Answer:
see explaination
Step-by-step explanation:
Using the formulla that
sum of terms number of terms sample mean -
Gives the sample mean as \mu=17.954
Now varaince is given by
s^2=\frac{1}{50-1}\sum_{i=1}^{49}(x_i-19.954)^2=9.97
and the standard deviation is s=\sqrt{9.97}=3.16
b) The standard error is given by
\frac{s}{\sqrt{n-1}}=\frac{3.16}{\sqrt{49}}=0.45
c) For the given data we have the least number in the sample is 12.0 and the greatest number in the sample is 24.1
Q_1=15.83, \mathrm{Median}=17.55 and Q_3=19.88
d) Since the interquartile range is Q_3-Q_1=19.88-15.83=4.05
Now the outlier is a number which is greater than 19.88+1.5(4.05)=25.96
or a number which is less than 15.83-1.5(4.05)=9.76
As there is no such number so the given sample has no outliers
The length and width of the new scale drawing is 36 inches and 24 inches respectively.
The given parameters:
- <em>Original scale of the soccer field, 1 inch : 12 yards</em>
The original length and width of the soccer field is calculated as follows;
1 inch : 12 yards
- original width = 6 x 12 yards = 72 yards
- original length = 9 x 12 = 108 yards
For the new scale of 1 inch : 3 yards, the new length and width are represented as;
<em>the </em><em>new width</em><em>:</em>
<em>the </em><em>new length</em><em>:</em>
Thus, the length and width of the new scale drawing is 36 inches and 24 inches respectively.
Learn more about scale drawing here:
