solution:
I choose 5 women from a pool of 10 in 10C2 ways.
I choose 5 men from a pool of 12 in 12C2 ways.
So total number of ways of choosing in 10C2 x 12C2. Now I need to arrange them in 5 pairs. This is where I have a different solution. The solution says that there are 5! ways to arrange them in pairs.
But I cant seem to understand why? My reasoning is that for first pair position I need to choose 1 man from 5 and 1 woman from 5. So for the first position I have 5 x 5 choices (5 for man and 5 for woman). Similarly for the second position I have 4 x 4 choices and so on. Hence the total ways are 5! x 5!
So I calculate the total ways as 10C2 * 12C2 * 5! * 5!. Can anyone point the flaw in my reasoning for arranging the chosen men and women in pairs.
Answer:
c= 35+25m
Step-by-step explanation:
The $35 is a one time payment and the 25 dollars is each month!
Hope this helps!
Answer:
18
Step-by-step explanation:
The centroid divides the median into 2 parts from the vertex to one point to the opposite side of the vertex where the median starts.
Put into simpler language. HB is twice as long as HF
If Hf is 6 then HB is 12. BF is the total length of both or 6 + 12 = 18
