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3 years ago

11

Determine the end behavior of each rational function below. Graph each function on the graphing calculator, and

1 answer:

melomori [17]3 years ago

5 0

Answer:

a) End behavior: As → ∞, () → . As → −∞, () → .

Looking at the ends of the graph, as goes to ∞ or −∞, gets

closer to .

b) End behavior: As → ∞, () → . As → −∞, () → .

Looking at the ends of the graph, as x goes to ∞ or −∞, gets

closer to .

c) End behavior: As → ∞, () → ∞, and as → −∞, () → −∞.

Looking at the ends of the graph, as goes to ∞, continues to increase

toward ∞, and as x goes to −∞, continues to decrease toward −∞.

Obs:. Graphics are attached

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Write the standard form of the line that passes through the given points. Include your work in your final answer. Type your answ

Nata [24]

Answer: $5x-3y=44$

Step-by-step explanation:

We know that , the equation of a line that passes through (a,b) and (c,d) is given by :_

$(y-b)=\dfrac{d-b}{c-a}(x-a)$

Standard form of equation of line = $Ax+By=C$

Given points = (7, -3) and (4, -8)

Then, the equation of a line that passes through the points . (7, -3) and (4, -8) is given by -

$(y-(-3))=\dfrac{-8-(-3)}{4-7}(x-7)$

$(y+3)=\dfrac{-8+3}{-3}(x-7)$ [∵ (-)(-)=(+)]

$(y+3)=\dfrac{-5}{-3}(x-7)$

$(y+3)=\dfrac{5}{3}(x-7)$

$3(y+3)=5(x-7)$

$3y+9=5x-35$

$9+35=5x-3y$

$44=5x-3y$

Or $5x-3y=44$

Hence, the required equation :- $5x-3y=44$

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3 years ago

Hat is the position of 7 in the number 876,543? A. The ten-thousands place B. The hundreds place C. The tens place D. The thousa

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As you can see in this diagram, the answer is A, the ten-thousands place.

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3 years ago

How many solutions does y-10 =2x have

Travka [436]

Y= 2x+10 would be the equation and it would have no solution because there's no value if x nor y

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3 years ago

In △ABC, D is a point on side AC¯¯¯¯¯¯¯¯ such that BD=DC and ∠BCD measures 70∘. What is the degree measure of ∠ADB?

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If angle BCD measures 70° then so does angle DBC (because you have formed an isoceles triangle inside the larger ΔABC and the two legs are equal so the two angles have to be equal. So we have a two 70° angles which leaves 40° for the 3rd angle, which is ∠BDC.

Since ∠BDC and ∠ADB are supplementary (180°) - that leaves 140° for ∠ADB and is our answer

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3 years ago

In the adjoining figure , APB and AQC are equilateral triangles. Prove that PC = BQ. ( Hint : <img src="https://tex.z-dn.net/?f=

just olya [345]

Answer:

See Below.

Step-by-step explanation:

Statements: Reasons:

$\displaystyle 1)\text{ } \Delta APB \text{ and } \Delta AQC \text{ are equilateral triangles}$ Given

$\displaystyle 2) \text{ } m \angle PAB = 60$ Definition of equilateral.

$3)\text{ } m \angle QAC = 60$ Definition of equilateral.

$4)\text{ } m\angle PAB = m\angle QAC$ Substitution

$5)\text{ } m\angle PAC=m\angle PAB+m\angle BAC$ Angle Addition

$\displaystyle 6)\text{ } m\angle QAB=m\angle QAC+m\angle BAC$ Angle Addition

$7)\text{ } m\angle QAB=m\angle PAB+m\angle BAC$ Substitution

$\displaystyle 8)\text{ } m\angle PAC=m\angle QAB$ Substitution

$9)\text{ } PA=BA$ Definition of equilateral

$10)\text{ } AC=AQ$ Definition of equilateral

$\displaystyle 11)\text{ } \Delta PAC \cong \Delta BAQ$ Side-Angle-Side Congruence*

$\displaystyle 12)\text{ } PC=BQ$ CPCTC

* SAS Congruence:

PA = BA

∠PAC = ∠QAB

AC = AQ

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2 years ago

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