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Otrada [13]
3 years ago
11

Determine the end behavior of each rational function below. Graph each function on the graphing calculator, and

Mathematics
1 answer:
melomori [17]3 years ago
5 0

Answer:

a) End behavior: As → ∞, () → . As → −∞, () → .

Looking at the ends of the graph, as goes to ∞ or −∞, gets

closer to .

b) End behavior: As → ∞, () → . As → −∞, () → .

Looking at the ends of the graph, as x goes to ∞ or −∞, gets

closer to .

c) End behavior: As → ∞, () → ∞, and as → −∞, () → −∞.

Looking at the ends of the graph, as goes to ∞, continues to increase

toward ∞, and as x goes to −∞, continues to decrease toward −∞.

Obs:. Graphics are attached

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Out of 100 employees at a company, 92 employees either work part time or work 5 days each week. There are 14 employees who work
Alexus [3.1K]

Answer: 0.02

Step-by-step explanation:

OpenStudy (judygreeneyes):

Hi - If you are working on this kind of problem, you probably know the formula for the probability of a union of two events. Let's call working part time Event A, and let's call working 5 days a week Event B. Let's look at the information we are given. We are told that 14 people work part time, so that is P(A) = 14/100 - 0.14 . We are told that 80 employees work 5 days a week, so P(B) = 80/100 = .80 . We are given the union (there are 92 employees who work either one or the other), which is the union, P(A U B) = 92/100 = .92 .. The question is asking for the probability of someone working both part time and fll time, which is the intersection of events A and B, or P(A and B). If you recall the formula for the probability of the union, it is

P(A U B) = P(A) +P(B) - P(A and B).

The problem has given us each of these pieces except the intersection, so we can solve for it,

If you plug in P(A U B) = 0.92 and P(A) = 0.14, and P(B) = 0.80, you can solve for P(A and B), which will give you the answer.

I hope this helps you.

Credit: https://questioncove.com/updates/5734d282e4b06d54e1496ac8

7 0
2 years ago
Please help asap<br><br> solve x^4+5x^2+4=0
const2013 [10]

Answer:

x=\pm i\text{ or }x=\pm2i

Step-by-step explanation:

So we have the equation:

x^4+5x^2+4=0

Let's let u be equal to x². So:

u^2+5u+4=0

Factor:

(u+1)(u+4)=0

Zero Product Property:

u+1=0\text{ or } u+4=0

Subtract:

u=-1\text{ or }u=-4

Replace:

x^2=-1\text{ or }x^2=-4

Take square root:

x=\pm\sqrt{-1}\text{ or }x=\pm\sqrt{-4

Simplify:

x=\pm i\text{ or }x=\pm2i

7 0
3 years ago
Find the value of x so that the function has the givin value<br><br> n(x)=2x+7, n(x)=17
Sunny_sXe [5.5K]

Answer: x=5

Step-by-step explanation:

Substitute 17 for n(x)

17=2x+7

Subtract 7 from both sides

10=2x

Divide each side by 2 to get the x by itself

x=5

6 0
3 years ago
Name and locate points in all four quadrants of the coordinate plane.
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Shiiii who’s that fine man
7 0
3 years ago
Coach Evans recorded the height, in inches of each player on his team. The results are shown.
marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile (Q_1)

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile (Q_3)

Terms in arranged in ascending order:

57,60,60,61,62,62,63,63,64

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

Q_1 is median of terms 57,60,60,61

Number of terms (n) = 4

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60

So, Q_1=60

So, 25% of the heights of a team is less than 60 inches

Q_3 is the median of terms 62,63,63,64

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63

So, Q_3=63

So, 75% of the heights of a team is less than 63 inches

Interquartile range = Q_3-Q_1=63-60=3

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0
3 years ago
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