1/10 of 3,000
(1/10)(3000/1)
=(1)(3000)/(10)(1)
=3000/10
=300
For this case we have the following functions:
f (x) = 36 + 4x
g (x) = x2 + 15
By matching both functions we have:
f (x) = g (x)
36 + 4x = x2 + 15
Rewriting we have:
x2 + 15 - 4x - 36 = 0
x2 - 4x - 21 = 0
Solving the polynomial we have:
(x-7) (x + 3) = 0
x = -3
x = 7
Taking the positive root we have:
x = 7
Answer:
They will have the same amount of money saved after:
x = 7 weeks
For one semester a School A-
750 + 200 = 950
For one semester at School B-
10 percent off of 1,000 is 900
School A- $950
School B- $900
I'd have to say the slop is - 1/24