Does the system have no solution?
1 answer:
Answer:
Step-by-step explanation:
Notice that in the second equation, the coefficient of is
times greater than in the first. Therefore, by making the coefficient of
in the second equation
times greater than in the first, it's impossible to only isolate one variable.
Therefore, when , there are no solutions to this system.
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F(x)= 0.02x^2 + 0.08x + 30.6
so for f(0) all that means is where you see x plug 0 for x..
f(0)= 0.02(0)^2+ 0.08(0) + 30.6
f(0)= 30.6
f(4)= 0.02(4)^2 + 0.08(4) + 30.6
f(10)= 0.02(10)^2 + 0.08(10) + 30.6
attached are calculated answers
so for f(0) all that means is where you see x plug 0 for x..
f(0)= 0.02(0)^2+ 0.08(0) + 30.6
f(0)= 30.6
f(4)= 0.02(4)^2 + 0.08(4) + 30.6
f(10)= 0.02(10)^2 + 0.08(10) + 30.6
attached are calculated answers
<em>The answer you are looking for is: </em>
<em>a= 247.75
</em>
<em>hope that helps!! </em>
<em>Have a wonderful day!!</em>
<em>a= 247.75
<em>hope that helps!! </em>
<em>Have a wonderful day!!</em>