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seraphim [82]
3 years ago
5

Need help please (50 points at stake) The farmer's plan is to fence in a strip of his land for herding his cattle so that it for

ms a square. He decides to place the four corner post of the fence and then place 15 posts between each corner post so that there is a distance of 8 and 1/8 feet between each post around the entire fenced-in area. Calculate the area and perimeter of this fenced-in area.
Mathematics
1 answer:
Fiesta28 [93]3 years ago
8 0

15 posts plus 2 corner posts = 17 posts. With 17 posts there would be 16 spaces each side.

The space between each is 8 1/8 feet.

The length of one side is the number of spaces multiplied by the distance between each space.

Total length of one side = 16 spaces x 8 1/8 feet = 130 feet

Area = length x width.

It’s a square shape so area = 130 x 130 = 16,900 square feet

Perimeter is the distance around the square, this would be the length of one side x the number of sides.

Perimeter = 130 x 4 = 520 feet

You might be interested in
Suppose that you had the following data set. 500 200 250 275 300 Suppose that the value 500 was a typo, and it was suppose to be
hodyreva [135]

Answer:

\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305

s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108

\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105

s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221

The absolute difference is:

Abs = |340.221-115.108|= 225.113

If we find the % of change respect the before case we have this:

\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%

So then is a big change.

Step-by-step explanation:

The subindex B is for the before case and the subindex A is for the after case

Before case (with 500)

For this case we have the following dataset:

500 200 250 275 300

We can calculate the mean with the following formula:

\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305

And the sample deviation with the following formula:

s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108

After case (With -500 instead of 500)

For this case we have the following dataset:

-500 200 250 275 300

We can calculate the mean with the following formula:

\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105

And the sample deviation with the following formula:

s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221

And as we can see we have a significant change between the two values for the two cases.

The absolute difference is:

Abs = |340.221-115.108|= 225.113

If we find the % of change respect the before case we have this:

\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%

So then is a big change.

8 0
4 years ago
Step by step on how to solve this problem
Andrew [12]
The correct answer is (x+2)(x-9) here are the steps :)
The middle number is -7 and the last number is -18z
Factoring means we want something like

(X+_) (X+_)
Which number go in the blanks?

We need two number that
•Add together to get -7
•Multiply to get -18

Can you think of the two numbers?

Try 2 and -9:
•2+-9=-7
•2*-9=-18


Fill the blanks in
And you get
(X+2)(x-9)
Hope this helps :)
3 0
3 years ago
What is the value of x in the equation ?
Eduardwww [97]

Answer:

<u>Part A:</u><u>  x = -24</u>

<u>Part B:  </u><u>n = 2</u>

Step-by-step explanation:

<u>Part A:</u>

The algebraic expression for: "StartFraction 2 Over 3 EndFraction left-parenthesis StartFraction one-half EndFraction. x plus 12 right-parenthesis equals left-parenthesis StartFraction one-half EndFraction left-parenthesis StartFraction one-third EndFraction x plus 14 right-parenthesis minus 3" will be ⇒ \frac{2}{3} (\frac{1}{2} x+12)=(\frac{1}{2} (\frac{1}{3} x+14)-3)

Multiply both sides by 6

∴ 6 * \frac{2}{3} (\frac{1}{2} x+12)=6*(\frac{1}{2} (\frac{1}{3} x+14)-3)

∴4*(\frac{1}{2} x+12)=3 (\frac{1}{3} x+14)-18

∴ 2x + 4*12 = x + 3 *14 - 18

∴ 2x - x = 3 * 14 - 18 - 4 * 12 = -24

<u>∴ x = -24</u>

============================================================

<u>Part B:</u>

The algebric expression for: "StartFraction one-half EndFraction left-parenthesis n minus 4 right-parenthesis minus 3 equals 3 minus left-parenthesis 2 n plus 3 right-parenthesis" will be ⇒ \frac{1}{2}(n-4)-3=3-(2n+3)

Multiply both sides by 2

(n-4) - 6 = 6 - 2(2n+3)

n - 4 - 6 = 6 - 4n - 6

Combine like terms

n + 4 n = 4 + 6

5n = 10

n = 10/5 = 2

<u>∴ n = 2</u>

5 0
4 years ago
Read 2 more answers
Please help!!!!!!!​
Serhud [2]

Answer:

152

Step-by-step explanation:

12+16=28 so 180 is the total and 180-28=<u>152</u>

<u />

3 0
3 years ago
PART 2 - Arithmetie Reasoning Onestion The pet store had 6 puppies selling for $104 each and 12 kittens selling for $24 each. To
BlackZzzverrR [31]

Answer:

The correct option is A) 13 to 3.

Step-by-step explanation:

Consider the provided information.

The pet store had 6 puppies selling for $104 each and 12 kittens selling for $24 each. Today, only 2 puppies and 8 kittens were left.

6-2 = 4 puppies sale

12-8 = 4 kittens sale

The cost of each puppies is $104.

Cost of 4 puppies:

4×$104=$416

The cost of each kittens is $24.

Cost of 4 kittens :

4×$24=$96

The ratio of sales of puppies to kittens is:

\frac{416}{96}

\frac{13}{3}

Hence, the ration of sales of puppies to kittens is 13/3.

Thus, the correct option is A) 13 to 3.

3 0
3 years ago
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