P = IRT
T=P/(IR)
hope helped
Answer:
1oc IS ur answer
Step-by-step explanation:
i think
Answer:
6523
Step-by-step explanation:
I'm assuming that the question is asking us to rearrange the numbers 5,3,2,6 to obtain the largest possible value that is odd.
In order for a number to have the largest value, the first digit of the number must he the largest possible value. In this case, we see that the largest value is 6, hence the number must begin with 6 i.e 6XXX
We can do the same for the next digit in the hundreds position by picking the largest possible remaining number. In this case, it is the number 5. So the number will look something like this: 65XX
We see that the only remaining numbers are 3 and 2.
Recall that for a number to be odd, the digit on the ones place must also be odd. Of the remaining numbers, only 3 is odd, hence the last number must be 3. i.e 65X3
Hence the last remaining number is 2
6523
A square matrix that is not invertible is called singular or degenerate.
Answer:
B. a = 5
Step-by-step explanation:
3(a - 4) + 1 = 9 - a
Distribute the 3 into the parenthesis.
3a - 12 + 1 = 9 - a
Add -12 and 1.
3a - 11 = 9 - a
Add a to both sides.
4a - 11 = 9
Add 11 to both sides.
4a = 20
Divide both sides by 4.
a = 5.
Proof:
3(a - 4) + 1 = 9 - a
Substitute variable.
3(5 - 4) + 1 = 9 - 5
Subtract inside parenthesis.
3(1) + 1 = 9 - 5
Multiply 3 and 1.
3 + 1 = 9 - 5
Add 3 and 1.
4 = 9 - 5
Subtract 5 from 9.
4 = 4.