Answer:
reactivity is NOT a physical property
Answer:
The Kc of this reaction is 311.97
Explanation:
Step 1: Data given
Kp = 0.174
Temperature = 243 °C
Step 2: The balanced equation
N2(g) + 3H2(g) ⇌ 2NH3(g)
Step 3: Calculate Kc
Kp = Kc *(RT)^Δn
⇒ with Kp = 0.174
⇒ with Kc = TO BE DETERMINED
⇒ with R = the gas constant = 0.08206 Latm/Kmol
⇒ with T = the temperature = 243 °C = 516 K
⇒ with Δn = number of moles products - moles reactants 2 – (1 + 3) = -2
0.174 = Kc (0.08206*516)^-2
Kc = 311.97
The Kc of this reaction is 311.97
The answer is actually Water Splitting! Hope this works:D
Since you have not included the given reaction, I am going to explain you how to solve these kind of problems.
1) The chemical equilibrium is a
dynamic process. It means that in an equilibrim reaction there are two rectaions,
the forward reaction and the reverse reaction whose velocities are the same.
2) The general equation of a a chemical reaction in equlibrium is:
aA + bB ⇄ cC + dDWhere A and B are the reactants, C and D are the products, and a, b, c, d, are the coefficientes in the
balanced equation.3) So, the
equilibrium law is:
![Keq= \frac{C]^c[D]^d}{[A]^a[B]^b}](https://tex.z-dn.net/?f=Keq%3D%20%5Cfrac%7BC%5D%5Ec%5BD%5D%5Ed%7D%7B%5BA%5D%5Ea%5BB%5D%5Eb%7D%20)
Where Keq is the constant of equilibrium
4) To complete the explanation, I am going to deal with an
example:
i) Consider the equlibrium reaction between hydrogen and iodine:
H₂ (g) + I₂(g) ⇄ 2HI(g)ii) The forward reaction is H₂ (g) + I₂(g) → 2HI(g)
iii) The reverse reaction is 2HI (g) → H₂ (g) + I₂(g)
iv) The
law of equilibrium is:
hi friend! its b, or a 1:2 ratio. i looked it up for help, and didn't have anything, so I did 1:2 and it was correct.