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earnstyle [38]
3 years ago
11

What is the correct prefix for 6?

Chemistry
1 answer:
Reil [10]3 years ago
3 0

Answer:

hex-

Explanation:

Prefix Prefix meaning Sample word

<em>hex-</em>           6                                  hexapod: having six legs, an insect, for      

                                                                   example.

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How many atoms are in the molecule beryllium carbonate
Vladimir79 [104]

Answer:

1

Explanation:

g00gle

6 0
3 years ago
Read 2 more answers
Two parts that make up a solution are... what
hjlf
Answer: All solutions have two parts: the solute and the solvent. The solute is the substance that dissolves, and the solvent is the substance that dissolves the solute.
Hope that helps (:
5 0
3 years ago
Classify each of the following possible reactions according to whether a precipitate will form or will not form.
elena-14-01-66 [18.8K]

Answer:

Reactions, 2, 3 and 5 make precipitates

Explanation:

1. The halogens always make aqueous salts with elements from group 1

2. Phosphate anion can make insoluble salts, the same as carbonate.

3. Nitrate anion always make aqueous salts

4. Sulfate anion makes aqueous salts except with Ag⁺, Pb⁺² and group 2

1. KI(aq) + NaCl(aq) → KCl(aq) + NaI(aq)

2. 2Na₃PO₄ (aq) + 3CoCl₂(aq) → 6NaCl(aq) + Co₃(PO₄)₂(s) ↓

3. Na₂CO₃ (aq) + CuCl₂ (aq) → 2NaCl (aq) + CuCO₃ (s) ↓

4. 2LiNO₃ (aq) + Na₂SO₄ (aq) → Li₂SO₄ (aq) + 2NaNO₃(aq)

5.  CrCl₂ (aq) + Li₂CO₃ (aq) → 2LiCl (aq) + Cr₂(CO₃)₂ (s) ↓

8 0
3 years ago
An electric kettle draws a current of 6.50 A while it is plugged into a 120-V
Umnica [9.8K]

Answer:

780 watts

Explanation:

formula to find power when given amps and voltage

P = A x V

=6.50a x 120V

= 780 W (watts)

7 0
3 years ago
G determine the concentration of an hbr solution if a 45.00 ml aliquot of the solution yields 0.6485 g agbr when added to a solu
Sunny_sXe [5.5K]

The molecular weight of silver bromide (AgBr) is 187.77 g/mole. The presence of the ions in solution can be shown as- AgBr (insoluble) ⇄Ag^{+} + Br^{-1}.

45.00 mL of the aliquot contains 0.6485 g of AgBr. Thus 1000 mL of the aliquot contains \frac{0.6485}{45}×1000 = 14.411 gm-mole. Thus the solubility product K_{sp}of AgBr = [Ag^{+}]×Br^{-}.

Or, 5.0×10^{-13} = S^{2} (the given value of solubility product of AgBr is 5.0×10^{-13} and the charge of the both ions are same).

Thus S = (5.00×10^{-13})^{1/2} = 7.071×10^{-7} g/mL.

Thus the concentration of Br^{-1} or HBr is 7.071×10^{-7} g/mL.

4 0
4 years ago
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